Try asking googleee cuz that’s hard siisss
Answer:
<h3>For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.</h3>
By De morgan's law
which is Bonferroni’s inequality
<h3>Result 1: P (Ac) = 1 − P(A)</h3>
Proof
If S is universal set then
<h3>Result 2 : For any two events A and B, P (A∪B) = P (A)+P (B)−P (A∩B) and P(A) ≥ P(B)</h3>
Proof:
If S is a universal set then:
Which show A∪B can be expressed as union of two disjoint sets.
If A and (B∩Ac) are two disjoint sets then
B can be expressed as:
If B is intersection of two disjoint sets then
Then (1) becomes
<h3>Result 3: For any two events A and B, P(A) = P(A ∩ B) + P (A ∩ Bc)</h3>
Proof:
If A and B are two disjoint sets then
<h3>Result 4: If B ⊂ A, then A∩B = B. Therefore P (A)−P (B) = P (A ∩ Bc) </h3>
Proof:
If B is subset of A then all elements of B lie in A so A ∩ B =B
where A and A ∩ Bc are disjoint.
From axiom P(E)≥0
Therefore,
P(A)≥P(B)
Answer:
The correct answer for this question is this one:
If the x position of the vertex for f(x) is k then :
1. f(k) => 4x+3=k, x = (k-3)/4 = (k/4)-(3/4)
2. x = k+3
3. x = (k+1)/2 = (k/2)-(1/2)
4. x = 2(k+2) = 2k+4
5. x = k+7
6. x = k-3
7. x = k-2
So the order depends on the original position of the vertex k, e.g for k=0 the positions would be:
1. -3/4
2. 3
3. -1/2
4. 4
5. 7
6. -3
7. -2
So, therefore, the order would be 6 7 1 3 2 4 5
Answer is 108 pages. 1/3 of an hr is 20 min. 20*3=60 which is an hr. 3+3=6. So then you get 6*18=108.
