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suter [353]
3 years ago
5

What is the complement of a 30 1/2 degree angle?

Mathematics
2 answers:
mario62 [17]3 years ago
6 0

Answer:

59 1/2

Step-by-step explanation:

azamat3 years ago
6 0

Answer:

i believe it's 59 1/2

Step-by-step explanation:

plz mark brainliest if you can

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Please help with the two questions above! I will give brainliest to the correct answers. Thanks!
aksik [14]

Answer:

In both the above questions, correct option is (D).

#$# THANK YOU #$#

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3 years ago
Question 3 of 20
olchik [2.2K]
I think it’s C but it could be D.. i would go with C tho
3 0
2 years ago
1 . a sequence in which a fixed amount is added on to get the next term arithmetic sequence 2 . an individual quantity or number
Dmitry [639]
T_n = a_1 + d(n-1)

If a = 4 and d = 3,

T_n = 4+ 3(n-1)

T_n = 4+ 3n-3

T_n = 3n + 1

---------------------------------------------------------------------------------------
Answer: The general equation for the nth term is 3n + 1.
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6 0
3 years ago
Hii! please help asap. i’ll give brainliest
grin007 [14]

only the mean

Step-by-step explanation:

The mean which by where you add all of the data 6+7+9+10+11+13+14/7 Equals 10 which is the middle value, making it the measure of center

6 0
3 years ago
Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal
lisabon 2012 [21]

Given the following functions below,

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}

Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

4 0
1 year ago
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