The figure shows a circle circumscribed around a triangle.
1 answer:
Option B is right perpendicular bisectors of the sides of the triangle
<h3>What circumcircle?</h3>If we draw a circle through all the vertices of a triangle then the circle obtained is the circumcircle of the given triangle. We have in a triangle there are some properties inherent.
One is the perpendicular bisectors of all sides are concurrent. These three concur at a point called the circumcentre of the triangle.
When we draw a perpendicular bisector for a side AB, we get that all points on the perpendicular bisector are equidistant from A and B.
When we take the point of intersection of the perpendicular bisector of AB and BC, we have the intersecting point S(say) is equidistant from A and B and also from B and C
In short, this is equidistant from all 3 vertices and hence is the centre of the circumcircle of triangle ABC
Therefore Option B is right perpendicular bisectors of the sides of the triangle.
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Answer: 2
Step-by-step explanation:
Recall from the laws of Logarithms:
Log a - Log b = Log ( a/b )
That means
Log 200 - Log 2 = Log ( 200/2)
= Log 100 , which could be written as
Log
Recall from laws of Logarithms:
Log = b Log a
Therefore:
Log = 2 Log 10
Also from law of Logarithm
Log 10 = 1
Therefore 2 Log 10 = 2 x 1
= 2