All categories

3 years ago

1/2 (4a + 10b) = c solve for b Can someone help me on this

Mathematics

2 answers:

Butoxors [25]3 years ago

7 0

Here is the answer I got: B=c/5 - 2a/5

Artyom0805 [142]3 years ago

7 0

1/2 (4a + 10b) = c

Remove the 1/2 by multiplying both sides by 2:

4a + 10b = 2c

Subtract 4a from both sides:

10b = 2c -4a

Divide both sides by 10:

b = (2c-4a)/10

SImplify by the fraction:

b = (c - 2a)/5

You might be interested in

Part A: If (7^2)^x = 1, what is the value of x? Explain your answer.

kotykmax [81]

For part a x=0 because anything to the power of 0 is 1
For part b any number could be x, because 7^0 is one and 1 to the power of anything will be 1
Hope this helps!

3 0

3 years ago

Need help!!!! asap.

frez [133]

Answer:

Step-by-step explanation:

Annoying to type out, take my word for it

7 0

3 years ago

If M is the set of all square numbers less than 80 and N is the set of all non-negative even numbers that are under 30, Write th

Nat2105 [25]

Answer:

Step-by-step explanation:

All square numbers are numbers formed by squaring a single number. If M is the set of all square numbers less than 80, then

M = (4, 9, 16, 25, 49, 64)

Even numbers are numbers that are divisible by 2 without remainder.

If N is the set of all non-negative even numbers that are under 30, then

N = (2, 4, 6, 8 ,10, 12, 14, 16,18,20, 22, 24, 26,28)

It will not include 30 because we want even numbers under 30

8 0

3 years ago

A hospital uses cobalt-60 in its radiotherapy treatments for cancer patients. Cobalt-60 has a half-life of 7

NeTakaya

Answer:

We have 197 g of Co-60 after 18 months.

Step-by-step explanation:

We can use the decay equation.

$M_{f}=M_{i}e^{-\lambda t}$

Where:

M(f) and M(i) are the final and initial mass respectively
λ is the decay constant (ln(2)/t(1/2))
t(1/2) is the half-life of Co
t is the time at the final amount of m

$M_{f}=228e^{-\frac{ln(2)}{7} 1.5}$

$M_{f}=197\: g$

<u>Therefore, we have 197 g of Co-60 after 18 months.</u>

I hope it helps you!

4 0

3 years ago

Which of the following sets of data will have the smallest Standard Deviation?

uranmaximum [27]

Answer: D

Step-by-step explanation:

Standard Deviation σ2 =

Σ(xi - μ)2/N

=(1 - 5.3)2 + ... + (9 - 5.3)2/10

=68.1/10

= 6.81

σ = √6.81

= 2.60959767014

B) σ2 =

Σ(xi - μ)2/N

=(3 - 61.7)2 + ... + (99 - 61.7)2/10

=58414.1/10

= 5841.41

σ = √5841.41

= 76.429117488036

C) (1 - 11.4)2 + ... + (1 - 11.4)2/10

=8758.4/10

= 875.84

σ = √875.84

= 29.59459410095

D) (79 - 79)2 + ... + (79 - 79)2/10

=0/10

= 0

σ = √0

= 0

I hope this helps, mark as Brainliest please.

6 0

3 years ago