Question

Identify the focus, directrix, and axis of symmetry of 11x=y^2

Answer 1

Answers

focus: (0, $\frac{11}{4}$)

directrix: x = $-\frac{11}{4}$

AOS: y = 0

Step-by-step explanation:

11x = y²

 x = $\frac{1}{11}$y²

 x = $\frac{1}{11}$(y - 0)² + 0

Vertex: (0, 0)

Axis of symmetry: y = 0

Focus: $\frac{1}{4p} = a$     a = $\frac{1}{11}$

$\frac{1}{4p} = \frac{1}{11}$

4p = 11

 p = $\frac{11}{4}$ so, focus is: (0, $\frac{11}{4}$)

Directrix: -p = $-\frac{11}{4}$ so, directrix is: x = $-\frac{11}{4}$