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kolbaska11 [484]
3 years ago
14

Identify the focus, directrix, and axis of symmetry of 11x=y^2

Mathematics
1 answer:
ale4655 [162]3 years ago
8 0

<u>Answers </u>

focus: (0, \frac{11}{4})

directrix: x = -\frac{11}{4}

AOS: y = 0

<u>Step-by-step explanation:</u>

11x = y²

 x = \frac{1}{11}y²

 x = \frac{1}{11}(y - 0)² + 0

Vertex: (0, 0)

Axis of symmetry: y = 0

Focus: \frac{1}{4p} = a     a = \frac{1}{11}

\frac{1}{4p} = \frac{1}{11}

4p = 11

 p = \frac{11}{4} so, focus is: (0, \frac{11}{4})

Directrix: -p = -\frac{11}{4} so, directrix is: x = -\frac{11}{4}




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