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3 years ago

Identify the focus, directrix, and axis of symmetry of 11x=y^2

Mathematics

1 answer:

ale4655 [162]3 years ago

8 0

Answers

focus: (0, $\frac{11}{4}$ )

directrix: x = $-\frac{11}{4}$

AOS: y = 0

Step-by-step explanation:

11x = y²

x = $\frac{1}{11}$ y²

x = $\frac{1}{11}$ (y - 0)² + 0

Vertex: (0, 0)

Axis of symmetry: y = 0

Focus: $\frac{1}{4p} = a$ a = $\frac{1}{11}$

$\frac{1}{4p} = \frac{1}{11}$

4p = 11

p = $\frac{11}{4}$ so, focus is: (0, $\frac{11}{4}$ )

Directrix: -p = $-\frac{11}{4}$ so, directrix is: x = $-\frac{11}{4}$

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Alternative Method
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