Answer:
x has a value of 71, making D the correct answer.
Step-by-step explanation:
Because this is an isosceles triangle, we know that the bottom two angles are equal. We also know that the sum of the angles inside a triangle will always come to 180°. With that in mind, we can simply subtract 38° from 180° and divide by two to get the correct answer.

So the correct answer is D, 71 degrees.
Answer:

Step-by-step explanation:
Starting from the y-intercept of
you do
by either moving four blocks <em>south</em><em> </em>over one block <em>west</em><em> </em>or four blocks <em>north</em><em> </em>over one block<em> east</em><em> </em>[<em>west</em> and <em>south</em> are negatives]. Next, we have to determine the types of inequality symbols that are suitable for this graph, which will be <em>less</em><em> </em><em>than</em><em> </em>and <em>greater</em><em> </em><em>than</em><em> </em>since this is a <em>dashed</em><em> </em><em>line</em><em> </em>graph. We then use the zero-interval test [test point (0, 0)] to ensure whether we shade the opposite portion [portion that does not contain the origin] or the portion that DOES contain the origin. At this step, we must verify the inequalities as false or true:
<em>Greater</em><em> </em><em>than</em>
☑
<em>Less</em><em> </em><em>than</em><em> </em>
![\displaystyle 0 < 4[0] - 2 → 0 ≮ -2](https://tex.z-dn.net/?f=%5Cdisplaystyle%200%20%3C%204%5B0%5D%20-%202%20%E2%86%92%200%20%E2%89%AE%20-2)
This graph is shaded in the portion of the origin, so you would choose the <em>greater</em><em> </em><em>than</em><em> </em>inequality symbol to get this inequality:

I am joyous to assist you anytime.
So, (weekly) she receives 1036.00.
The question is asking to find out the (annual) salary which is a year.
There are about 52 weeks in a year.
To find the amount being payed annually we multiply 1036 by 52
=53,872.
So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.