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3 years ago

11

jordan has been offered two summer jobs. one job pays 7 owr hour. the other 50 a week plus 5 per hour. how many hours would jord

an have to work for the same amount?

1 answer:

mart [117]3 years ago

6 0

He would have to work 24 weeks to get the same amount from each job.

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Jay currently has a balance of $2,375 on her credit card. If she must make a minimum monthly payment of 5.8% of her total balanc

Papessa [141]

Answer:

$137.75

Step-by-step explanation:

question is 'what is 5.8% of 2375'

'what' means assign a variable

'is' means an equal sign

'of' means to multiply

p = .058 x 2375

p = 137.75

*You could do the following: p = 5.8 x 2375 and get 13775 but you have to remember to move the decimal point two places to the left

4 0

2 years ago

erik [133]

$2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha$

$1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}$

$3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x$

8 0

2 years ago

Three times a number increased by 8 is no more than the number 4 find the number

loris [4]

The answer is less than or equal to -4. Because -4+8=4

3 0

2 years ago

What is the measure of angle C, m

Blizzard [7]

51°
Angles that are opposite to another angle are equal

7 0

1 year ago

Simplify the expression

erastova [34]

Answer : A

We need to simplify the given expression

Lets factor numerator first

$2x^2-5x-3$ =(2x+1)(x-3)

$x^2+8x+15$ =(x+5)(x+3)

Now we factor the denominator

$x^2+x-20$ =(x+5)(x-4)

$2x^2+9x+4$ =(2x+1)(x-4)

Now we simplify it

$\frac{(2x+1)(x-3)}{(x+5)(x-4)} * \frac{(x+5)(x+3)}{(2x+1)(x-4)}$

Now cancel out same factors. so we left with

$\frac{(x+3)(x-3)}{(x+4)(x-4)} }$

Now multiply the factors

$\frac{x^2-9}{x^2-16} }$

6 0

2 years ago