#1<span> Plug equations 4, 5, 6, and 7 into equation 3
To better combine like terms ... rearange the numbers
combine like terms (y's and constants cancel out)
Divide by 5
Plug this back into equations 5 and 7
#2 </span><span>Apply concepts of density based on area and volume in modeling ... Mathematically proficient students can apply the mathematics they know to solve problems arising in ... In Grade 3, students used modeling to solve real-world problems involving perimeter of polygons.
#3 </span><span>D Ira built his model using cross sections that were cut parallel to the base what shape was each cross section
</span>
Answer:
y=2x+10
Step-by-step explanation:
In line equations its helpful to write your line in the form y = ax + b. This helps because a is always the gadient of the line and b is always the y intercept.
In this case it is y=2x+3
All parallel lines have the same gradient. The gradient of this line = 2.
If the line crosses the x axis at x=-5, then when x =-5 y = 0.
If you put all this in the form y =ax + b you get 0 = 2(-5) +b
So all you need to do to find b is rearrange. b = 10.
Therefore your line has gradient 2 and y intercept 10.
y = 2x + 10
Given: BO : OY = 5:8. Coordinate B is located at (4,2,) ; O is located at (57/8,-3) and Y is located at (x,y).
We have to determine the coordinate Y.
We will use cross section formula which states:
The coordinates 
are divided in the ratio 
by the Coordinate A. So, the coordinates of A are given by the formula:
Here, 
x = 12.125
Now, 
y = -11
So, the coordinate is Y(12.125, -11).
Answer:
847π mm³
Step-by-step explanation:
The volume of a cone is exactly <em>one third </em>the volume of a cylinder with the same radius and height. The volume of our cylinder is 2541 mm³, so the cone inside it must have a radius of 1/3 × 2541 = 847 mm³
