3 years ago

What is the equation of a line perpendicular to the y axis.

Mathematics

1 answer:

ehidna [41]3 years ago

8 0

The line perpendicular to the y-axis is the x-axis.

Required equation is y = 0

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the 15 multi pack

Step-by-step explanation:

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3 years ago

2x − y = −4→10x − 5y = −20 3x 5y = 59→3x 5y = 59 13x = 39 which equation can replace 3x 5y = 59 in the original system and still

malfutka [58]

13x = 39 can replace 3x + 5y = 59 in the original system and still produce the same solution.

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3 years ago

The area of the sandbox is 56 2/3 square feet. The width is 8 1/2 feet. What is the length? Hint: Divide area by length

sertanlavr [38]

Answer:

20/3 ft or 6 2/3 ft

Step-by-step explanation:

A = 56 2/3 sq ft

W = 8 1/2 ft

L = ?

A = LW

L = A/W

$L = \dfrac{A}{W}$

$L = \dfrac{56~\frac{2}{3}~sq~ft}{8~\frac{1}{2}~ft}$

Change the mixed numbers into fractions.

$a\frac{b}{c} = \dfrac{ac + b}{c}$

$L = \dfrac{\frac{56 \times 3 + 2}{3}}{\frac{8 \times 2 + 1}{2}}$

$L = \dfrac{\frac{170}{3}}{\frac{17}{2}}$

$L = \dfrac{170}{3} \div \dfrac{17}{2}$

$L = \dfrac{170}{3} \times \dfrac{2}{17}$

$L = \dfrac{170 \times 2}{3 \times 17}$

$L = \dfrac{17 \times 10 \times 2}{3 \times 17}$

$L = \dfrac{10 \times 2}{3}$

$L = \dfrac{20}{3}$

Answer: 20/3 ft or 6 2/3 ft

4 0

4 years ago

Line a has a slope of<br> 7/5<br><br> . Line b is parallel to line a. What is the slope of line b?

DerKrebs [107]

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Hint :

Parallel lines have same slopes.

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$slope \: \: of \: \: line \: \: b \: = \frac{7}{5} \\$

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6 0

3 years ago