Answer:1/8
Step-by-step explanation:
12.5% = 12.5/100 = 0.125=0.125/1×1000/1000=125/1000=1/8
The +3 is the vertical and the +5 tells you horizontal. so this graph moves 3 up and 5 left. But since it only wants vertical that would be the +3
Answer:
Answers are the last step of every problem
Step-by-step explanation:
1) 27+y<10
y<-17
2) 4x+5≥29
4x≥24
x≥6
3) 6y+1>7
6y>6
y>1
4) 3p+1≤-1
3p≤-2
p≤-2/3
5) 9≥12-x
-3≥-x
3≤x
6) 3-5x>13
-5x>10
x>-2
7) 5/6x-1/2<1/3
5x-3<2
5x<5
x<1
8) 7/8-1/4x≥3/4
7-2x≥6
-2x≥-1
x≤1/2
9) 4/5y-1/5>3
4/5y>16/5
4y>16
y>4
10) 3x+3>7+x
2x+3>7
2x>4
x>2
11) 8-x<10-2x
8+x<10
x<2
12) 11+x≤7+5x
11≤7+4x
4≤4x
1≤x
Answer:
200 trucks
Step-by-step explanation:
There's about 15 trucks in the 2nd row from the right. It looks to be about 1/2 the size of the rows to the left of it.
So based on that, I can assume, there are about 30 trucks in each of the 5 long rows, and both of the short rows would make up about another 30 trucks total. There are various trucks parked along the perimeter or between rows, so I estimated there would be about 20 of those based on 3 per row.
30 x 5 = 150 +30 = 180 + 20 = 200
Factoring a quadratic of the form ax^2+bx+c requires that you find two values, j and k, such that jk=ac and j+k=b. Then you replace bx with jx and kx in the original equation. Then you factor the first and second pair of terms.
So in your case...
x^2+6x+8
ac=jk=8 and b=j+k=6 so j and k must be 2 and 4 so your equation becomes:
x^2+2x+4x+8 now factor 1st and 2nd pair of terms...
x(x+2)+4(x+2) which is equal to:
(x+4)(x+2)
....
x^2-3x-18, ac=jk=-18, b=j+k=-3, so j and k must be -6 and 3 so
x^2+3x-6x-18
x(x+3)-6(x+3)
(x-6)(x+3)
...
x^2-7x+12, jk=12, j+k=-7, so j and k must be -3 and -4 so
x^2-3x-4x+12
x(x-3)-4(x-3)
(x-4)(x-3)