Answer:
a) 0.778
b) 0.9222
c) 0.6826
d) 0.3174
e) 2 drivers
Step-by-step explanation:
Given:
Sample size, n = 5
P = 40% = 0.4
a) Probability that none of the drivers shows evidence of intoxication.



b) Probability that at least one of the drivers shows evidence of intoxication would be:
P(X ≥ 1) = 1 - P(X < 1)
c) The probability that at most two of the drivers show evidence of intoxication.
P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)
d) Probability that more than two of the drivers show evidence of intoxication.
P(x>2) = 1 - P(X ≤ 2)
e) Expected number of intoxicated drivers.
To find this, use:
Sample size multiplied by sample proportion
n * p
= 5 * 0.40
= 2
Expected number of intoxicated drivers would be 2
Answer:
<h3>
∠XYZ = 102</h3><h3>
</h3>
Step-by-step explanation:
<u>1st step is to solve x from ΔWXY</u>
∠W + ∠X + ∠Y = 180
where ∠W = 5x + 2
∠X = 7x + 4
∠Y = 180 - (15x - 18)
= 198 - 15x
now plugin values into the equation:
5x + 2 + 7x + 4 + 198 - 15x = 180
combine similar terms:
5x + 7x - 15x = 180 - 2 - 4 - 198
simplify:
-3x = -24
x = -24 / -3
x = 8
<u>2nd step is to substitute x = 8 into ∠XYZ</u>
∠XYZ = 15x - 18
∠XYZ = 15(8) - 18
∠XYZ = 102
Answer:
56 minutes
Step-by-step explanation: