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3 years ago

12

PLEASE HELP ASAP! What are the solutions to the system of equations?

1 answer:

musickatia [10]3 years ago

8 0

Y=2x

so what you do is sub 2x for y in the top equation

x^2+(2x)^2=5
x^2+4x^2=5
5x^2=5
divide both sides by 5
x^2=1
sqrt both sides
x=1 or -1

sub back

y=2x

y=2(-1)
y=-2

y=2(1)
y=2

the solutions are (1,2) and (-1,-2)

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snow_tiger [21]

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4 years ago

Nutka1998 [239]

Answer:

Step-by-step explanation:

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8 0

3 years ago

1. What is the mode of this dot plot? 2. How many 2nd graders are in the class?

kramer

Answer:

Mode- yellow

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Step-by-step explanation:

The mode is the variable with the largest value.

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6 0

3 years ago

Read 2 more answers

Suppose the FAA weighed a random sample of 20 airline passengers during the summer and found their weights to have a sample mean

Orlov [11]

Answer:

Step-by-step explanation:

Given Parameters

Mean, $x$ = 180

total samples, n = 20

Standard dev, $\sigma$ = 30

$\alpha$ = 1 - 0.95 = 0.05 at 95% confidence level

Df = n - 1 = 20 - 1 = 19

Critical Value, $t_\alpha$ , is given by

$t_{c}=t_{\alpha, df} = t_{0.05,19} = 1.729$

a).

Confidence Interval, $\mu$ , is given by the formula

$\mu = x +/- t_c \times \frac{s}{\sqrt{n} }$

$\mu = 180 +/- 1.729 \times \frac{30}{\sqrt{20} }$

$\mu = 180 +/-11.5985$

$191.5985 > \mu > 168.4015$

b).

Critical Value, $t_{\alpha/2}$ , is given by

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Confidence Interval, $\mu$ , is given by

$\mu = x +/- t_c \times \frac{s}{\sqrt{n} }$

$\mu = 180 +/- 2.093 \times \frac{30}{\sqrt{20} }$

= 180 +/- 14.0403

= 165.9597 < $\mu$ < 194.0403

8 0

3 years ago