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3 years ago

What is the equation of the line that is parallel to the line y = x + 4 and passes through the point (6, 5)?

Mathematics

1 answer:

zhuklara [117]3 years ago

3 0

Answer:

y = x - 1

Step-by-step explanation:

Slope = 1

b = 5 - (1)(6)

b = -1

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What is the value of x?

garik1379 [7]

Answer:

x=4

Step-by-step explanation:

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3 years ago

Is the relation a function?

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3 years ago

Pls help I need to find out the equation

Sauron [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Does anyone know what the slope should be

Lemur [1.5K]

The slope is 4/3.

rise/run
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3 years ago

What is the slope of a line perpendicular to the line whose equation is 3x+6y=-183x+6y=−18. Fully reduce your answer.

schepotkina [342]

Answer:

Step-by-step explanation:

The given equation of line is

$3x+6y=-18$

We need to find the slope of a line which is perpendicular to the given line.

The given equation can be rewritten as

$3x+6y+18=0$ ...(i)

If a line is defined as $ax+bx+c=0$ , then the slope of the line is

$m=-\dfrac{a}{b}$

In equation (i), a=3, b=6 and c=18. So, slope of the line is

$m_1=-\dfrac{3}{6}=-\dfrac{1}{2}$

Let $m_2$ be the slope of perpendicular line.

We know that product of two perpendicular line is -1.

$m_1\cdot m_2=-1$

$(-\dfrac{1}{2})\cdot m_2=-1$

Multiply both sides by -2.

$m_2=2$

Therefore, the slope of perpendicular line is 2.

6 0

3 years ago