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oksian1 [2.3K]
3 years ago
15

What is the equation of the line that is parallel to the line y = x + 4 and passes through the point (6, 5)?

Mathematics
1 answer:
zhuklara [117]3 years ago
3 0

Answer:

y = x - 1

Step-by-step explanation:

Slope = 1

b = 5 - (1)(6)

b = -1

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What is the value of x?
garik1379 [7]

Answer:

x=4

Step-by-step explanation:

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3 years ago
Is the relation a function?
Margaret [11]
No; a domain value has two range values.

x = -2 then y = 1 and 2

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8 0
3 years ago
Pls help I need to find out the equation
Sauron [17]

Answer:

2x + 1.5y = 15

Step-by-step explanation:

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7 0
3 years ago
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Does anyone know what the slope should be
Lemur [1.5K]
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5 0
3 years ago
What is the slope of a line perpendicular to the line whose equation is 3x+6y=-183x+6y=−18. Fully reduce your answer.
schepotkina [342]

Answer:

2

Step-by-step explanation:

The given equation of line is

3x+6y=-18

We need to find the slope of a line which is perpendicular to the given line.

The given equation can be rewritten as

3x+6y+18=0      ...(i)

If a line is defined as ax+bx+c=0, then the slope of the line is  

m=-\dfrac{a}{b}

In equation (i), a=3, b=6 and c=18. So, slope of the line is

m_1=-\dfrac{3}{6}=-\dfrac{1}{2}

Let m_2 be the slope of perpendicular line.

We know that product of two perpendicular line is -1.

m_1\cdot m_2=-1

(-\dfrac{1}{2})\cdot m_2=-1

Multiply both sides by -2.

m_2=2

Therefore, the slope of perpendicular line is 2.

6 0
3 years ago
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