Note the squares...
13 is possible because it is a sum of two squares (integers) 9 + 4 .. use (0,3) & (2,0) ... get the square roots and place on different coordinate axes... for a simpler value.
but there is none for 15...
there is one for 18 ...
18 = 3^2 + 3^2 ... try (0,3) ,(3,0) , (3,6), (6,3).
The answer is 3 you just divide 24 by 8
This is a quadratic function:
f(x)=ax²+bx+c
We have three points:
(0 , 77.6)
(5 , 78)
(10 , 78.6)
Then, we make the function wiht these points:
(0 , 77.6)
x=0
f(x)=77.6
a(0)²+b(0)+c=77.6
c=77.6
(5 , 78)
a(5)²+b(5)+77.6=78
25a+5b=78-77.6
25a+5b=0.4 (1)
(10 , 78.6)
a(10)²+b(10)+77.6=78.6
100a+10b=78.6-77.6
100a+10b=1 (2)
With the equations (1) and (2) we have a system of equations:
100a+10b=1
25a + 5b=0.4
We solve this system of equations by method of elimination.
100a+10b=1
-4(25a+5b=0.4)
-----------------------------
-10b=-0.6 ⇒ b=-0.6/-10=0.06
100a+10b=1
-2(25a+5b=0.4)
----------------------------
50a = 0.2 ⇒ a=0.2/50=0.004
We have a, b and c:
a=0.004
b=0.06
c=77.6
Therefore, the quadratic funtion is:
f(x)=0.004x²+0.06x+77.6
x=year of the beginning of the interval - 1980
The life expectancy for females born between 1995 and 2000 is when x=1995-1980=15
Therefore:
f(15)=0.004(15)²+0.06(15)+77.6
f(15)=0.004(225)+0.06(15)+77.6
f(15)=79.4
The life expectancy for females born between 2000 and 2005 is when:
x=2000-1980=20
therefore:
f(20)=0.004(20)²+0.06(20)+77.6
f(20)=1.6+1.2+77.6
f(20)=80.4
Answer:
The funtion is:
f(x)=0.004x²+0.06x+77.6
x=year of the beginning of the interval - 1980
The life expectancy for females born between 1995 and 2000 is 79.4 years.
The life expectancy for females born between 2000 and 2005 is 80.4 years.
P=2l+2w
150(2)+170(2)
300+340
640 m
Answer:
![k=\frac{\sqrt[3]{v}}{2}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B%5Csqrt%5B3%5D%7Bv%7D%7D%7B2%7D)
Step-by-step explanation:
we know that
If two figures are similar, the the ratio of its volumes is equal to the scale factor elevated to the cube
Let
z------> the scale factor
x------> the volume of the dilated solid
y------> the volume of the original solid
so
![z^{3}=\frac{x}{y}](https://tex.z-dn.net/?f=z%5E%7B3%7D%3D%5Cfrac%7Bx%7D%7By%7D)
we have
![z=k](https://tex.z-dn.net/?f=z%3Dk)
![x=v\ units^{3}](https://tex.z-dn.net/?f=x%3Dv%5C%20units%5E%7B3%7D)
![y=8\ units^{3}](https://tex.z-dn.net/?f=y%3D8%5C%20units%5E%7B3%7D)
substitute
![k^{3}=\frac{v}{8}](https://tex.z-dn.net/?f=k%5E%7B3%7D%3D%5Cfrac%7Bv%7D%7B8%7D)
![k=\frac{\sqrt[3]{v}}{2}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B%5Csqrt%5B3%5D%7Bv%7D%7D%7B2%7D)