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nika2105 [10]
4 years ago
9

Veronica was recently diagnosed with a heart condition. Her doctor's bill was $4,200 for the diagnostics. Her policy has a $250

deductible and a 80/20 coinsurance provision up to $10,000 and then the insurance pays 100% thereafter. In total, how much will Veronica pay for her diagnosis?
Mathematics
1 answer:
Nadusha1986 [10]4 years ago
4 0

Answer:

$1040

Step-by-step explanation:

As 80/20 insurance policy is a form of coinsurance in which deductible is satisfied first and then the client would pay 20% of additional medical costs and the remaining 80% is paid by the insurance company. Under the current scenario, Veronica will bear an amount of $250 and $790(i.e. 20% of the amount after deductible), totaling to $1040.

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A wire 15 cm long is cut into two pieces. The longer piece is 3.cmidonger than the shorter piece.Find the length of the shorter
Andre45 [30]

A piece of wire is cut into two pieces. That means each part would be assigned an unknown variable. Let one part be x and the other part be y.

That means,

x+y=15\operatorname{cm}

If the longer part is x, and the longer part is 3cm longer than the shorter part, then we would have the following;

\begin{gathered} x+y=15 \\ x=y+3 \\ \text{This is because x is 3cm longer,} \\ So\text{ the length of x would be y+3} \end{gathered}

We can now refine the equation as follow;

\begin{gathered} \text{Where;} \\ x=y+3 \\ x+y=15 \\ y+3+y=15 \\ 2y+3=15 \\ \text{Subtract 3 from both sides;} \\ 2y+3-3=15-3 \\ 2y=12 \\ \text{Divide both sides by 2;} \\ \frac{2y}{2}=\frac{12}{2} \\ y=6 \\ \text{When;} \\ x+y=15 \\ x+6=15 \\ \text{Subtract 6 from both sides;} \\ x+6-6=15-6 \\ x=9 \end{gathered}

ANSWER:

The length of the shorter piece of wire is 6cm

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What is 14.95 + 10% tip
Ostrovityanka [42]
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Say x is the number

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Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.
Leviafan [203]

Answer:

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Step-by-step explanation:

we know that

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

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sin^{2}(\alpha)+cos^{2}(\alpha)=1

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we have

sin(x)=\frac{1}{2}

we know that

sin^{2}(x)+cos^{2}(x)=1

substitute

(\frac{1}{2})^{2}+cos^{2}(x)=1

cos^{2}(x)=1-\frac{1}{4}

cos^{2}(x)=\frac{3}{4}

cos(x)=\frac{\sqrt{3}}{2}

step 2

Find tan(x)

tan(x)=sin(x)/cos(x)

substitute

tan(x)=1/\sqrt{3}

step 3

Find sin(y)

we have

cos(y)=\frac{\sqrt{2}}{2}

we know that

sin^{2}(y)+cos^{2}(y)=1

substitute

sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1

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step 4

Find tan(y)

tan(y)=sin(y)/cos(y)

substitute

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step 5      

Find tan(x+y)

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

substitute

tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73

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If we replace y with x2cos x and solve for y', we can conclude that the derivative is
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Y = x^2 cos x

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