Answer:
10 and 15
Step-by-step explanation:
Let 'x' and 'y' are the numbers we need to find.
x + y = 25 (two numbers whose sum is 25)
(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)
The solutions of the this system of equations are the numbers we need to find.
x = 25 - y
1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y
6y + 6(25-y) = (25-y)y
6y + 150 - 6y = 25y - (y^2)
y^2 - 25y + 150 = 0 quadratic equation has 2 solutions
y1 = 15
y2 = 10
Thus we have
:
First solution: for y = 15, x = 25 - 15 = 10
Second solution: for y = 10, x = 25 - 10 = 15
The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).
1. 100
2. 20
3. 2
4. 150
5. 0
6. 21
7. 16
Answer:
24
Step-by-step explanation:
Let n = number of sides
15n = 360
divide both sides of the equation by 15
n = 24
<h3>
Answer: Choice C</h3>
Explanation:
The x intercepts or roots are x = 3 and x = 5, which lead to the factors x-3 and x-5 respectively.
Multiplying out those factors gets us this:
(x-3)(x-5)
x(x-5)-3(x-5)
x^2-5x-3x+15
x^2-8x+15
