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Galina-37 [17]
3 years ago
12

Y=2x+4 use in a graph

Mathematics
1 answer:
AlekseyPX3 years ago
6 0
The slope is 2 and the y intercept is 4
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a. more samples need to be compared

c. the samples are not similar

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7/2  but as a mixed number 3 1/2

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Sharika can finish the work in 6 days and Palkey can do the same work in 8 days. They both worked together for for 2 days then P
Rufina [12.5K]

Answer:

Sharika needs 2.5 days to finish the remaining work

Step-by-step explanation:

Sharika can do a work in 6 days palkey can do it in 8 days

Then the amount of work sharika can do in 1 day = 1/6

And the amount of work palkey can do in 1 day = 1/8

The amount of work both of them can do together in 1 day = 1/6 + 1/8

= 7/24

The amount of work both of them can do together in 2 day = (2× 7/24)

= 7/12

Since Palkey left the work,the amount of

work remaining for Sharika to do alone = (1 - 7/12 )

= 5/12

The number of days Sharika take to finish the remainig work. = (5/12 ÷ 1/6 )

= 5/2 days

Therefore, Sharika needs 2.5 days to finish the remaining work.

5 0
3 years ago
When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
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