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Andre45 [30]
3 years ago
11

Solve the equationshow your work9 + 12m = 6 + 15(m - 1)

Mathematics
1 answer:
Fudgin [204]3 years ago
7 0

Answer: m=6

Step-by-step explanation:

9+12m=6+15\left(m-1\right)

6+15\left(m-1\right)=15m-9

9+12m=15m-9

subtract 9 on both sides

9+12m-9=15m-9-9

12m=15m-18

subtract 15m on both sides

12m-15m=15m-18-15m

-3m=-18

divide by -3 on both sides

\frac{-3m}{-3}=\frac{-18}{-3}

since \frac{-a}{-b}=\frac{a}{b}

\frac{-18}{-3}=6

m=6

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The graph is attached below.

Step-by-step explanation:

<em>As you have not added the graph, so I will be solving the function for a graph.</em>

Given the function

f\left(x\right)=x-\frac{1}{x^2}-x-6

x-\mathrm{axis\:interception\:points\:of\:}-\frac{1}{x^2}-6:

\mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0

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\mathrm{No\:x-axis\:interception\:points}

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\mathrm{Domain\:of\:}\:-\frac{1}{x^2}-6\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)\end{bmatrix}

\mathrm{Since}\:x=0\:\mathrm{is\:not\:in\:domain}

\mathrm{No\:y-axis\:interception\:point}

\mathrm{Asymptotes\:of}\:-\frac{1}{x^2}-6:\quad \mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-6

\mathrm{Range\:of\:}-\frac{1}{x^2}-6:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)

The graph is attached below.

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