The first one is -763.1 and the second one is -24
The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
To learn more on quadratic functions: brainly.com/question/5975436
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Your answer is 25% <span> of change in the price of a radio</span>
Answer:
Bert has $45.
Step-by-step explanation:
I have no real strategy, except for that I used guess and check. How did I do this? Well, since I am in 5th Grade, I don't know algebra very well, so I made an organized chart and checked all the numbers that had to be a multiple and could be divided equally by 5, 3 and when a third of that number was subtracted by 6, it was a fifth of the orginal number. Thats how I got 45.
Checking this answer:
It is always important to check your answer after finishing the problem, so this is how I checked my answer:
1. 45 divided by 3 = 15
2. 15 - 6 = 9, and 9 is 1/5 of 45
Bert has $45.