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ratelena [41]
3 years ago
12

Please solve this -10+1/3y>2/3

Mathematics
1 answer:
Marianna [84]3 years ago
3 0

Solving -10+\frac{1}{3}y>\frac{2}{3} we get y>32

Step-by-step explanation:

We need to solve the expression:

-10+\frac{1}{3}y>\frac{2}{3}

Solving the expression

Adding 10 on both sides:

-10+\frac{1}{3}y>\frac{2}{3}\\=-10+\frac{1}{3}y+10>\frac{2}{3}+10\\=\frac{1}{3}y>\frac{2+30}{3}\\=\frac{1}{3}y>\frac{32}{3}\\

Multiplying 3 on both sides

=\frac{1}{3}y\times3>\frac{32}{3}\times3\\=y>32

So, Solving -10+\frac{1}{3}y>\frac{2}{3} we get y>32

Keywords: Solving Inequality

Learn more about solving inequality at:

  • brainly.com/question/9590016
  • brainly.com/question/1465430
  • brainly.com/question/4192226

#learnwithBrainly

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\huge\mathfrak{\underline{answer:}}

\large\bf{\angle ACD = 105°}

__________________________________________

\large\bf{\underline{Here:}}

  • BCD is an isosceles right triangle , right angled at D
  • ABC is an equilateral triangle

\large\bf{\underline{To\:find:}}

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\large\bf{In\: triangle\:ABC:}

❒ Sum of all angles is 180° , since it is an equilateral triangle all the three angles would be same

\large\bf{\underline{So}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼\angle ACB = \frac{180}{3}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼\angle ACB = 60°}

\large\bf{In\: triangle\:BDC}

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\bf{⟼\angle DBC =\angle DCB }(Isosceles triangle)

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