All categories

4 years ago

Combine the like terms to create an equivalent expression. 4n+6+n-2

Mathematics

2 answers:

DerKrebs [107]4 years ago

7 0

Answer:

5n+4

Step-by-step explanation:

NemiM [27]4 years ago

3 0

5n+4 seems to be the answer

You might be interested in

PLEASE ANSWER THIS MATH QUESTION FOR THOSE MATH LOVERS :)

viva [34]

Remark

The general formula for these types of questions is

(x1 + k(x2 - x1) ) , (y1 + k(y2 - y1))

Problem 1 -- Point G

Givens

(x1,y1) is the starting point which in this case is (-3, -3)

(x2,y2) is the ending point which in this case is (6 , -3)

k = 1/4

Sub and solve

(-3 + 1/4(6 - - 3), - 3+ 1/4(- 3 - - 3)

(-3 + 1/4(9) , - 3 + 1/4 (-3 + 3)

(-3 + 9/4, -3 + 1/4(0) )

(-12/4 + 9/4 , -3)

(-3/4 , - 3) Answer

Problem 2 Point F Much harder

Givens

(x1,y1) = (-3 , -1)

(x2,y2) = (6, - 3)

k = 3/4

Sub and solve

(-3 + 3/4(6 - - 3) , -1 + 3/4(-3 - - 1) )

(-3 + 3/4(9) , - 1 + 3/4(-2) )

(-3 + 27/4 , -1 - 6/4 )

(-12/4 + 27/4, -4/4 - 6/4)

( 15/4 , - 10/4) <<<<<< Answer Part B

4 0

3 years ago

Read 2 more answers

49.02 _____ forty-nine and nineteen thousands

Arturiano [62]

Answer:

49.02 > 49.019

Step-by-step explanation:

It's true :)

Think of 49.02 as 49.020.

Don't you think that 49.020 > 49.019? It makes sense! :)

6 0

4 years ago

Read 2 more answers

A: Top 6% of scores B: Scores below the top 6% and above the bottom 59% C: Scores below the top 41% and above the bottom 17% D:

Natalija [7]

Answer:

The numerical limits for a B-grade is between 81 and 92

Step-by-step explanation:

Here in this question, our task is to find the numerical limits for B grade. This means the range between a test taker would be scored a B grade

Please check attachment for complete solution and explanation

3 0

3 years ago

PLEASE HELP!!! NEED THIS ANSWERED!!!!

Nezavi [6.7K]

Exclusive events, for OR we can add probabilities.

P(O or B) = 0.49 + 0.20 = 0.69

Answer 0.69

4 0

3 years ago

Can someone tell me what is 6=2(y+2)

tatuchka [14]

Distribute the 2 through the parentheses

on the right side of the equation.

2(y) is 2y and 2(2) is 4.

So the problem now reads 6 = 2y + 4.

Now we can subtract 4 from both

sides of the equation to get 2 = 2y.

Now divide both sides of the

equation by 2 and 1 = y.

8 0

3 years ago

Read 2 more answers