Can someone please help me with this⁉️ the math question is in the picture and I’m so confused.

I will mark brainliest ,thank, and rate to to the best answer!Please help! ASAP

Over [174]

Answer:

1st, 3rd, and 6th

Step-by-step explanation:

Let's look at each statment...

1.) Correct

Explanation: 10 percent of the students at the school participate in soccer. If 140 is 10% of the number of students at the school, there is more than 140 students at this school.

2.) Incorrect

Explanation: We've already established that the # of students at the school is <u>more</u> than 140.

3.) Correct

Explanation: 10% as a decimal is 0.1 Divide 140 by 0.1 and you get 1,400. So, the total number of students is 1,400.

4.) Incorrect

Explanation: We've already established that the number of students is 1,400, not 290.

5.) Incorrect

Explanation: We've already established that the number of students is 1,400, not 150.

6.) Incorrect

Explanation: If the percent was a ratio, it would be 10:100 or 10/100. This is because a whole percent is 100% and the percent of students who play soccer is 10%.

7.) Correct

Explanation: We've already established that the ratio would be 10:100 or 10/100. Thus, this is correct.

I hope this helps! :)

3 0

3 years ago

Read 2 more answers

9m + 7n2 - 4 + 6m + 5

Ksivusya [100]

Answer:

15m+7n2+1

Step-by-step explanation:

You can add 9m and 6m. Then you will get 15m. Then you would add -4 and 5, you would get 1. So the new equation would be the answer. Since 7n2 doesn’t have another variable to connect to.

8 0

3 years ago

Prove this <br><br> 1-tan^2x/1+tan^2x=cos^2x-sin^2x

tatiyna

Answer:

see explanation

Step-by-step explanation:

Using the identity

tan x = $\frac{sinx}{cosx}$

Consider the left side

$\frac{1-tan^2x}{1+tan^2x}$

= $\frac{1-\frac{sin^2x}{cos^2x} }{1+\frac{sin^2x}{cos^2x} }$ ( multiply numerator and denominator by cos²x to clear fractions

= $\frac{cos^2x-sin^2x}{cos^2x+sin^2x}$ ← ( cos²x + sin²x = 1 ]

= cos²x - sin²x

= right side , thus proven

7 0

3 years ago

Brody is making a necklace,bracelet and anklet out of beads. She has green, blue, purple and silver beads. How many different pi

liraira [26]

Answer:

4 x 3 = 12

Step-by-step explanation:

5 0

4 years ago

A large square consists of four identical rectangles and a small square. The area of the larg square is 49 cm2 and the length of

trapecia [35]

Answer:

The area of the small square is 1 cm^2

Step-by-step explanation:

The large square consist in four identical rectangles and one small square.

Then the area of the small square will be equal to the difference between the area of the large square and the areas of the rectangles.

Because we have 4 equal rectangles, if R is the area of one rectangle, and S is the area of the large square, the area of the small square will be:

area = S - 4*R

We know that the area of the large square is 49 cm^2

Then:

S = 49cm^2

Remember that the area of a square of side length K is:

A = K^2

Then the side length of the large square is:

K^2 = 49 cm^2

K = √(49 cm^2) = 7cm

And we know that the diagonal of one rectangle is 5cm.

Remember that for a rectangle of length L and width W, the diagonal is:

D = √(L^2 + W^2)

Then:

D = √(L^2 + W^2) = 5cm

And for how we construct this figure, we must have that the length of the rectangle plus the width of the rectangle is equal to the side length of the large square, then:

L + W = 7cm

L = (7cm - W)

Replacing this in the diagonal equation, we get:

√((7cm - W)^2 + W^2) = 5cm

(7cm - W)^2 + W^2 = (5cm)^2 = 25cm^2

49cm^2 - 14cm*W + W^2 + W^2 = 25cm^2

2*W^2 - 14cm*W + 49cm^2 = 25cm^2

2*W^2 - 14cm*W + 49cm^2 - 25cm^2 = 0

2*W^2 - 14cm*W + 24cm^2 = 0

We can solve this for W using the Bhaskara's formula, the solutions are:

$W = \frac{-(-14cm) \pm \sqrt{(-14cm)^2 - 4*2*(24cm^2)} }{2*2} = \frac{14cm \pm 2cm}{4}$

Then we have two solutions, and we only need one (because the length will have the other value)

We can take:

W = (14 cm + 2cm)/4 = 4cm

Then using the equation:

L + W = 7cm

L + 4cm = 7cm

L = 7cm - 4cm = 3cm

L = 3cm

Now remember that the area of one rectangle of length L and width W is:

R = L*W

Then the area of one of these rectangles is:

R = 4cm*3cm = 12cm^2

Now we can compute the area of the small square:

area = S - 4*R = 49cm^2 - 4*12cm^2 = 1cm^2

The area of the small square is 1 cm^2

3 0

3 years ago