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3 years ago

Describe a situation that matches the equation 2(-8)=16

Mathematics

1 answer:

borishaifa [10]3 years ago

3 0

Answer:

The little drummer boy wanted to solve a math problem for Christmas so he asked Santa and he gave him 2(-8) which the little drummer boy evaluated to equal 16.

Step-by-step explanation:

You just have to be creative.

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Question: A book contains 10 photograph , some in color and some in black-and-white. Each

padilas [110]

Answer:

Step-by-step explanation:

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4 years ago

A temperature of 1.64◦F corresponds to Answer in units of ◦C.

Liula [17]

Answer:

(1,64 °F − 32) × 5/9 = 73,333 °C

7 0

4 years ago

If c is the hypotenuse of a right triangle,find the missing side. If necessary, round to the nearest hundredth. c=sqrt(155), b=s

Lunna [17]

A^2 + 31 = 155 - I squared each of b and c for those numbers
a^2 = 155 - 31
a^2 = 124
a = 4 * sqrt(31)

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4 years ago

Given the function f(x) = 4(2)x, section a is from x = 1 to x = 2 and section b is from x = 3 to x = 4. part

Aliun [14]

A. Average rate of change for x=1 to 2: 4(2²)-4(2)=16-8=8; from x=3 to 4: 4(2⁴)-4(2³)=64-32=32.
b. Section b is 32/8=4 times greater. As the exponent of 2 increases, the gaps between consecutive powers of 2 gets wider and therefore the rate of change is greater.

6 0

3 years ago

The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the

erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes is 0.4786.

Step-by-step explanation:

The random variable X is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, β = 19 minutes.

The random variable X follows an Exponential distribution with parameter $\lambda=\frac{1}{\beta}=\frac{1}{19}$ .

The probability distribution function of X is:

$f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...$

Compute the value of the event (X > 14) as follows:

$P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786$

Thus, the probability that the wait time is greater than 14 minutes is 0.4786.

7 0

3 years ago