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UkoKoshka [18]
3 years ago
10

Refer to the triangle below. If a = 4 and b = 6, solve for c. show work Also, give the unsimplified radical form answer and then

the decimal form answer rounded to the nearest hundredth.​

Mathematics
1 answer:
9966 [12]3 years ago
5 0

Look at the image below where I labeled the sides

To solve this you must use Pythagorean theorem:

a^{2} +b^{2} =c^{2}

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 4

b = 6

c = unknown

^^^Plug these numbers into the theorem

4^{2} +6^{2} =c^{2}

simplify

16 + 36 = x^{2}

52 = x^{2}

To remove the square from x take the square root of both sides to get you...

√52 = x  

^^^Unsimplified radical

2√13

^^^Simplified radical

7.21

^^^Rounded to hundedths

Hope this helped!

~Just a girl in love with Shawn Mendes

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Read 2 more answers
George and Riley are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges.
worty [1.4K]

The cost of small box of oranges is $7.

The cost of large box of oranges is $13.

<u>Step-by-step explanation:</u>

It is given that,

3 small boxes of oranges and 14 large boxes of oranges for a total of $203.

11 small boxes of oranges and 11 large boxes of oranges for a total of $220.

Let us take,

  • The cost of small box of oranges = x
  • The cost of large box of oranges = y

<u>The system of equations are framed as :</u>

3x + 14y = 203  ---------(1)

11x + 11y = 220  ---------(2)

<u>To solve these equations for x and y values :</u>

Multiply equation (1) by 11 and equation (2) by 3

Subtract eq(2) from eq(1),

 33x + 154y = 2233

- <u>(33x + 33y = 660)  </u>

  <u>        121 y = 1573  </u>

⇒ y = 1573 / 121

⇒ y = 13

∴ The cost of large box of oranges is $13.

Substitute y=13 in the eq(1),

⇒ 3x + 14(13) = 203

⇒ 3x + 182 = 203

⇒ 3x = 203 - 182

⇒ 3x = 21

⇒ x = 21 / 3

⇒ x = 7

∴ The cost of small box of oranges is $7.

<u />

7 0
2 years ago
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