Option B i.e. Non-Euclidean
Hey!
You're right! This equation can definitely be solved by performing two operations on both sides. Let me show you how it's done.
First, let's write out our equation.
<span><em>Original Equation :</em>
</span>x + 53 = 15
Now that that's done, we'll be performing two operations on both sides. The operation we'll want to do is subtracting both sides of the equation by 53. We do this to get x on its own.
<em>Original Equation :</em>
x + 53 = 15
<em>New Equation {Added Subtract 53 to Both Sides} :</em>
x + 53 - 53 = 15 - 53
Now we have to solve the equation. Let's do the left side first.
<em>Left Side of the Equation :</em>
x + 53 - 53
<em>Left Side of the Equation {Solved} :</em>
x
Now, we'll solve the right side of the equation.
<em>Right Side of the Equation :</em>
15 - 53
<em>Right Side of the Equation {Solved} :</em>
-38
Now we can put both solutions to both sides of the equation together.
<em>New Equation :</em>
x = -38
Since this cannot be simplified any farther, this is our final answer. And that's it!
<em>So, now we know that in the equation x + 53 = 15,</em> x = -38
Hope this helps!
- Lindsey Frazier ♥
You can set up a system of equations with x being the smaller number and y being the larger number. So the first equation would be 2y=5x-14 and the second equation would be x=y-2. You can solve by substitution and substitute y-2 into the x in the first equation to get 2y=5(y-2)-14. You can solve this out and it ends up simplifying to y=8. So you know the larger number is 8. So since the larger number is 8 and they are consecutive even integers, the smaller number must be 6. So the two numbers would be 6 and 8.
Answer:
1
Step-by-step explanation:
