3 years ago

Decide which of the triangles are a right triangle. The figures are now drawn to scale

Mathematics

1 answer:

Kruka [31]3 years ago

3 0

Answer: triangle A

Step-by-step explanation:

Please give me brainliest

You might be interested in

Which of the following is a non-real complex number?

Nat2105 [25]

A I think Sorry if it’s wrong

8 0

2 years ago

Simplify the expression. write the answer using scientific notation 4(6.2x10^11)

Veseljchak [2.6K]

Answer:
= 2.48 × 10¹²
(scientific notation)

= 2.48e12
(scientific e notation)

= 2.48 × 10¹²
(engineering notation)
(trillion; prefix tera- (T))

= 2480000000000
<span>(real number)</span>

7 0

2 years ago

Read 2 more answers

A movie rental service is $5 a month after a one time start up fee of $60. Wrote an equation in slope-intercept form modeling th

alisha [4.7K]

Answer:

y=60+5x and you would have spent $120

Step-by-step explanation:

6 0

2 years ago

If the x axis is positive and the y is zero what’s quadrant or axis is it in?

Alecsey [184]

Quadrant 1

Hope this helps!
Brainliest is much appreciated!

5 0

1 year ago

Read 2 more answers

A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain

AysviL [449]

Answer:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

Step-by-step explanation:

For this case we have the following value:

$R = 0.0498 \frac{Kpa}{Km}$

We can convert this first to $\frac{Kpa}{m}$ like this:

$R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}$

Now we use the fact the the pressure is defined as $P =\frac{F}{A}$ , whre P is the pressure, F the force and A the area, so then $Kpa= \frac{KN}{m^2}$ and then we can replace this:

$R=0.0000498 \frac{KN}{m^3}$

Now from definition of work we know that $W= Fd$ where W is the work, F the force and d the distance, so then is equivalent $KN =\frac{KJ}{m}$

And if we replace this into the equation we got:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

4 0

3 years ago