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3 years ago

Help please. (I need a answer for this)

Mathematics

1 answer:

Katarina [22]3 years ago

5 0

Answer:

D. An input (x) can only be with one output (y).

Step-by-step explanation:

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Please help me, What is the 6th term of the geometric sequence 1024, 528, 256...?

scoundrel [369]

The geometric sequence is B: 32

5 0

3 years ago

2x - 2y = 22 find the value of y when x equals 2

Vika [28.1K]

Answer:

y=-9

Step-by-step explanation:

If x equals 2, then we can substitute that into the equation, resulting in the equation 2*2-2y=22

We can solve for multiplication first:

4-2y=22

Then we can subtract four on both sides, canceling out the four on the left side:

-2y=18

Now to isolate y, we divide both sides by -2, resulting in the solution:

y=-9

Hope this helps!

6 0

3 years ago

Read 2 more answers

What is r ÷ p equal to?

marshall27 [118]

Answer:

if those are variables they can equal anything you want like r=4 and p=2 r/p = 2

Step-by-step explanation:

7 0

3 years ago

Darrin graphs the following inequality: y > -3x -5. Does the side of the line with all solutions (the shaded region) include

Anarel [89]

Yes it does include the test point (0, 0)

equation: y > -3x -5

<h3>Find y-intercept:</h3>

y > -3(0) -5

y > -5

<h3>Find x-intercept:</h3>

y > -3x -5

<u>switch sides</u>

-3x - 5 < 0

-3x < 5

<u>Multiply both sides by -1 reverses the inequality</u>

x > -5/3

Thus, the following (0, 0) comes under the following x > -5/3 and y > -5

3 0

2 years ago

A basket contains three green apples and six red apples. three of the apples are selected at random. what is the probability tha

Dominik [7]

Solution: We are given that a basket contains three green apples and six red apples.

Three apples are randomly selected from the basket.

Now the probability of selecting first apple green is $\frac{3}{9} =\frac{1}{3}$

The probability of selecting second apple green is $\frac{2}{8} = \frac{1}{4}$

The probability of selecting third apple green is $\frac{1}{7}$

Therefore, the probability of selecting three green apples is:

$\frac{1}{3} \times\frac{1}{4} \times\frac{1}{7} =0.0119$ or 1.19%

Now how many red apples must be added to the basket in order to make the above probability smaller than 0.1%

If we add 11 red apples to the basket, then there will be 17 red apples and 3 green apples in the basket. Therefore, the probability of selecting three green apples if three apples are randomly selected is:

$\frac{3}{20} \times\frac{2}{19} \times\frac{1}{18} = 0.0009$ or 0.09%

Therefore, we need to add 11 red apples to the basket to make this probability smaller than 0.1%

8 0

3 years ago