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Inessa [10]
2 years ago
12

last year there were b pies baked for the bake sale. This year there were 194 pies baked. Using b write an expression for the to

tal number of pies baked in the two years
Mathematics
1 answer:
muminat2 years ago
6 0

Answer:

b+194=pies

Step-by-step explanation:

take the number of pies baked this year then add the b and then you get p(pies)

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The price of an item has been reduced h 45% the original price was $49
borishaifa [10]

Answer:

$26.95, you save  $22.05

Step-by-step explanation:

$49 x 0.45 = $22.05 savings, 49 - 22.05 = 26.95

3 0
3 years ago
Which figure has the greatest perimeter?​
Umnica [9.8K]

Figure A: 5•3=15

Figure B: 3•6=18

Figure C: 4•4=16

Figure D: 4•3=12

Figure B has the largest perimeter

4 0
3 years ago
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
3 years ago
I just need someone to check my answers, I did all the work but I'm not sure even though I checked my work 3 times but that's no
Lisa [10]

Answer:

yea in my opinon u are right but im not a expert in math.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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