Question

What is the product of (3y^-4)(2y^-5)

Answer 1

Answer:

$=\frac{6}{y^9}$

Step-by-step explanation:

$\mathrm{Apply-\:exponent-\:rule}:\quad \:a^b\times \:a^c=a^{b+c}\\y^{-4}y^{-5}=\:y^{-4-5}\\=3\times\:2y^{-4-5}\\\\Simplify \: -4-5\\=3\times \:2y^{-9}\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\\y^{-9}=\frac{1}{y^9}\\=3\times \:2\times \frac{1}{y^9}\\\mathrm{Multiply\:fractions}:\quad \:a\times \frac{b}{c}=\frac{a\:\times \:b}{c}\\=\frac{1\times \:3\times \:2}{y^9}\\\mathrm{Multiply\:the\:numbers:}\:1\times \:3\times \:2=6\\\\=\frac{6}{y^9}$