A book result sells for $28 if the book is on sale for 20% off how much the sale

Snowcat [4.5K]

A. The ratio of the person's shadow to their height is 6:2 or 3:1, so the height of the shadow is 360/3 or 120 m.
B. The model car's length divided by the ratio to the real car, which is 8.5/0.8 = 10.625 cm long.

6 0

3 years ago

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Solve 4(-4x- 3)> 36

wariber [46]

Answer:

x=3

Step-by-step explanation:

Simplifying

4(4x + -3) = 36

Reorder the terms:

4(-3 + 4x) = 36

(-3 * 4 + 4x * 4) = 36

(-12 + 16x) = 36

Solving

-12 + 16x = 36

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.

-12 + 12 + 16x = 36 + 12

Combine like terms: -12 + 12 = 0

0 + 16x = 36 + 12

16x = 36 + 12

Combine like terms: 36 + 12 = 48

16x = 48

Divide each side by '16'.

x = 3

Simplifying

x = 3

8 0

3 years ago

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Parker went shopping for a new pair of sneakers. Sales tax where he lives is 5%. The price of the pair of sneakers is $23. Find

Elina [12.6K]

23 x 5% =

23 x 0.05= 1.15 (total sales tax)

23 + 1.15= $24.15 (total price)

5 0

3 years ago

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How much more? To the nearest tenth, it holds __ cubic centimeters more than the other glass.

Andreyy89

Answer:

Two more cm. ALl you need to do now is convert it to cubic cm because I do not know how to do that.

Step-by-step explanation:

4 0

3 years ago

The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So

tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 $\times 10^{-6}$ .

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

$P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........$

where, n = number of trials (samples) taken = 18 Southwest flights

r = number of success = at least 13 flights arrive late

p = probability of success which in our question is probability that

flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X $\geq$ 13)

P(X $\geq$ 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= $\binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}$

= $\binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}$

= 2.5196 $\times 10^{-6}$ .

7 0

3 years ago