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Finger [1]
4 years ago
9

How do I do the problem 6(n+4)-4

Mathematics
1 answer:
Naddik [55]4 years ago
6 0

Answer:

3n+10

Step-by-step explanation:

6(n+4)-4

PEMDAS

start with parenthesizes

6 x n = 6n

6 x 4 = 24

so we have

6n+24-4

subtract the 4

6n+20

simplify by dividing by common factor

6n/2 =3n

20/2 =10

3n+10

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Answer:

a) B

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3 years ago
∠EFG and ∠GFH are a linear​ pair, m∠EFG=3n+23​, and m∠GFH=2n+32. What are m∠EFG and m∠​GFH?
NARA [144]

the measures of the angles are:

  • m∠EFG = 98°
  • m∠GFH = 82°
<h3>How to find the measures of the angles?</h3>

Two angles are a linear pair if their measures add up to 180°.

Then we will have that:

∠EFG + ∠GFH = 180

Here we know that:

m∠EFG=3n+23

m∠GFH=2n+32

Replacing that we get:

3n + 23 + 2n + 32 = 180

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n = 125/5 = 25

Then the measures of the angles are:

m∠EFG=3n+23 = 3*25 +23 = 98°

m∠GFH=2n+32 = 2*25 + 32 = 82°

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2 years ago
Answer this in pictures and number of words
qaws [65]

Answer: Tom's solution is incorrect.

Step-by-step explanation:

When you add 3/6 + 1/2 it equals ?.

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So we must have 6 as our common denominator.

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So 1 x 3 = 3.

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1 does not equal 4/12 or 1/3. So it makes it Incorrect.

What you should say:

Tom is incorrect, it is because 3/6 + 1/2 = 1, 1 does not equal 4/12 or 1/3. So, it makes it reasonable for the correct answer to be Incorrect

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insens350 [35]

Answer:

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