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jenyasd209 [6]
3 years ago
9

Can somebody help me please​

Mathematics
2 answers:
jeka943 years ago
8 0
The y intercept is (0,0.4) the x intercept is (0.3, 0)
serious [3.7K]3 years ago
5 0

Answer: y-int ( 0, 0.4 )      x-int ( 0.3, 0 )

Step-by-step explanation:

Given in the graph

X axis and Y axis.

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Find the equation of the line that is parallel to the line x + 5y = 10 and passes through the point (1, 3).
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The equation of the line that is parallel to the line x + 5y = 10 and passes through the point (1, 3) in slope intercept form is y = \frac{-1}{5}x + \frac{16}{5}

<h3><u>Solution:</u></h3>

Given that a line is parallel to line x + 5y = 10 and passes through the point (1, 3)

We have to find the equation of line

<em><u>The slope intercept form is given as:</u></em>

y = mx + c  -------- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

<em><u>Let us first find the slope of line</u></em>

Given equation of line is x + 5y = 10

5y = -x + 10\\\\y = \frac{-1}{5}x + \frac{10}{5}\\\\y = \frac{-1}{5}x + 2

On comparing the above equation of line with slope intercept form,

m = \frac{-1}{5}

We know that slopes of parallel lines are equal

So the slope of line parallel to given line is also m = \frac{-1}{5}

<em><u>Let us find the equation of line with slope m = -1/5 and passes through the point (1, 3)</u></em>

\text {substitute } m=\frac{-1}{5} \text { and }(x, y)=(1,3) \text { in eqn } 1

3 = \frac{-1}{5} \times 1 + c\\\\15 = -1 + 5c\\\\16 = 5c\\\\c = \frac{16}{5}

<em><u>Thus the required equation is:</u></em>

\text {substitute } m=\frac{-1}{5} \text { and } c=\frac{16}{5} \text { in eqn } 1

y = \frac{-1}{5}x + \frac{16}{5}

Thus the required equation of line is found

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Dont use this website

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