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ahrayia [7]
3 years ago
10

Suppose that y varies directly with x and y 12 when x--2. What is x when y -6?

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

Answer:

The ordered pair that satisfies this problem is (1, -6); x = 1 when y = -6.

Step-by-step explanation:

Please, rewrite your question as follows:

"Suppose that y varies directly with x and y = 12 when x = -2. What is x when

y = -6?"  The " = " sign must be included.

The pertinent proportional relationship is y = kx, where k is the constant of proportionality.

We must find k here.  Let y = 12 and x = -2.  Then 12 = k(-2), or k = -6.

Then the relationship is y = -6x.

Now let y = -6 and find x:      -6 = -6x, or x = 1.

The ordered pair that satisfies this problem is (1, -6)

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<h2>Answer:</h2>

The quadratic function are:

 option: A   A)  y(y + 4) - y = 6

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<h2>Step-by-step explanation:</h2>

We know that the general equation of a quadratic equation in terms of a variable x is given by:

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A)

y(y + 4) - y = 6

On simplifying the terms we have:

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Hence, option: A is correct.

B)

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Hence, it is a linear equation.

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it could also be written as:

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Hence, option: C is correct.

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which is again a linear equation.

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