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ahrayia [7]
3 years ago
10

Suppose that y varies directly with x and y 12 when x--2. What is x when y -6?

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

Answer:

The ordered pair that satisfies this problem is (1, -6); x = 1 when y = -6.

Step-by-step explanation:

Please, rewrite your question as follows:

"Suppose that y varies directly with x and y = 12 when x = -2. What is x when

y = -6?"  The " = " sign must be included.

The pertinent proportional relationship is y = kx, where k is the constant of proportionality.

We must find k here.  Let y = 12 and x = -2.  Then 12 = k(-2), or k = -6.

Then the relationship is y = -6x.

Now let y = -6 and find x:      -6 = -6x, or x = 1.

The ordered pair that satisfies this problem is (1, -6)

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Answer:

Step-by-step explanation:

A line perpendicular to the given line has a slope that is the negative inverse of the reference line.  

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The reference slope is -(2/3).  The negative inverse is (3/2), which will be the slope of a perpendicular line.  We can write the new line as:

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Any value of b will still result in a line that is perpendicular.  But we want a value of b that will shift the line so that it intersects the point (-3,-5).  Simply enter this point in the above equation and solve for b.

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