The width of the rectangle is 2 meters
9 times 52 = 468 hope that helped!!
Answer:
T = 47.1875°C
Step-by-step explanation:
Given:
Surrounding temp, Ts = 100°C
Initial Temperature ,T0= 20°C
Increase in temperature = 15°C
Final temperature, T = 20 + 15 = 35°C
Time, t = 9 seconds
Let's take Newton's law of cooling:

We'll solve for k

Divide both sides by -5


Let's now find the temperature of the ball after 18 seconds in boiling water.
Use the Newton's equation again:




T = 47.1875°C
Temperature of the ball after 18 seconds in boiling water is 47.1875°C
The difference is 105
3^2 - 2 + 7 =
(3 x 3) - 2 + 7 =
9 - 2 + 7 = 14
5^3 - 4^2 + 10 =
( 5 x 5 x 5) - ( 4 x 4) + 10
125 - 16 + 10 = 119
119 - 14 = 105