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3 years ago

14

Find the distance between the points (-3, 4) and (7,4).

1 answer:

Rufina [12.5K]3 years ago

7 0

Answer:

10 is the correct answer

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1/2a+(−7)+1/2a+ 1/3 <br> what is the value of A?

siniylev [52]

I reduced the equation to a - 6 (2/3)

4 0

3 years ago

A: What are the solutions to the quadratic equation x^2+9=0?

Nataliya [291]

Answer:

Part A)

x=-3i

x=3i

Part B)

(x+3i)(x-3i)

Step-by-step explanation:

Given:

Part A)

x^2+9=0

x^2=-9

x= √-9

x=√-1 *√9

x=± i *3

x=±3i

Part B)

x^2+9=0

x^2 - (-9)=0

x2-(3i)^2=0

(x-3i)(x+3i)=0 !

3 0

3 years ago

B\7+12=-8 helpppppppp

vodka [1.7K]

Answer:

b = -152

Step-by-step explanation:

7 + 12 = 19
Plug 19 in: $\frac{b}{19} = -8$
Multiply each side by 19 to cancel out the 19 under b. It should now look like this: b = -152

I hope this helps!

8 0

3 years ago

PLEASE ANSWER ASAP WILL MARK BRAINLIEST

Alja [10]

Answer:

the first one is the answer

3 0

3 years ago

Read 2 more answers

\large -\frac{2}{3}x+3=\frac{2}{3}x+\frac{1}{3}

german

Answer:

$\boxed {x = 2}$

Step-by-step explanation:

Solve for the value of $x$ :

$-\frac{2}{3}x + 3 = \frac{2}{3}x + \frac{1}{3}$

-Take $\frac{2}{3}x$ and subtract it from $-\frac{2}{3}x$ :

$-\frac{2}{3}x + 3 -\frac{2}{3}x = \frac{2}{3}x - \frac{2}{3}x + \frac{1}{3}$

$-\frac{4}{3}x + 3 = \frac{1}{3}$

-Subtract both sides and convert $3$ to a fraction:

$-\frac{4}{3}x + 3 - 3 = \frac{1}{3} - 3$

$-\frac{4}{3}x = \frac{1}{3} - \frac{9}{3}$

Since both $\frac{1}{3}$ and $\frac{9}{3}$ have the same denominator, then you would subtract the numerator:

$-\frac{4}{3}x = \frac{1 - 9}{3}$

$-\frac{4}{3}x = \frac{8}{3}$

-Multiply both sides by $-\frac{3}{4}$ , which is the reciprocal of $-\frac{4}{3}$ :

$x = \frac{8}{3} (-\frac{3}{4})$

$x = \frac{-8(-3)}{3 \times 4}$

$x = \frac{24}{12}$

-Divide $24$ by $12$ :

$x = \frac{24}{12}$

$\boxed {x = 2}$

So, therefore, the value of $x$ is $2$ .

5 0

3 years ago