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trapecia [35]
3 years ago
14

Find the distance between the points (-3, 4) and (7,4).

Mathematics
1 answer:
Rufina [12.5K]3 years ago
7 0

Answer:

10 is the correct answer

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1/2a+(−7)+1/2a+ 1/3 <br> what is the value of A?
siniylev [52]
I reduced the equation to a - 6 (2/3)
4 0
3 years ago
A: What are the solutions to the quadratic equation x^2+9=0?
Nataliya [291]

Answer:

Part A)

x=-3i

x=3i

Part B)

(x+3i)(x-3i)

Step-by-step explanation:

Given:

Part A)

x^2+9=0

x^2=-9

x= √-9

x=√-1 *√9

x=± i *3

x=±3i

Part B)

x^2+9=0

x^2 - (-9)=0

x2-(3i)^2=0

(x-3i)(x+3i)=0 !

3 0
3 years ago
B\7+12=-8 helpppppppp
vodka [1.7K]

Answer:

b = -152

Step-by-step explanation:

  1. 7 + 12 = 19
  2. Plug 19 in: \frac{b}{19} = -8  
  3. Multiply each side by 19 to cancel out the 19 under b. It should now look like this: b = -152

I hope this helps!

8 0
3 years ago
PLEASE ANSWER ASAP WILL MARK BRAINLIEST
Alja [10]

Answer:

the first one is the answer

3 0
3 years ago
Read 2 more answers
\large -\frac{2}{3}x+3=\frac{2}{3}x+\frac{1}{3}
german

Answer:

\boxed {x = 2}

Step-by-step explanation:

Solve for the value of x:

-\frac{2}{3}x + 3 = \frac{2}{3}x + \frac{1}{3}

-Take \frac{2}{3}x and subtract it from -\frac{2}{3}x:

-\frac{2}{3}x + 3 -\frac{2}{3}x = \frac{2}{3}x - \frac{2}{3}x + \frac{1}{3}

-\frac{4}{3}x + 3 = \frac{1}{3}

-Subtract both sides and convert 3 to a fraction:

-\frac{4}{3}x + 3 - 3 = \frac{1}{3} - 3

-\frac{4}{3}x  = \frac{1}{3} - \frac{9}{3}

Since both \frac{1}{3} and \frac{9}{3} have the same denominator, then you would subtract the numerator:

-\frac{4}{3}x  = \frac{1 - 9}{3}

-\frac{4}{3}x  = \frac{8}{3}

-Multiply both sides by -\frac{3}{4}, which is the reciprocal of -\frac{4}{3}:

x = \frac{8}{3} (-\frac{3}{4})

x = \frac{-8(-3)}{3 \times 4}

x = \frac{24}{12}

-Divide 24 by 12:

x = \frac{24}{12}

\boxed {x = 2}

So, therefore, the value of x is 2.

5 0
3 years ago
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