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3 years ago

PLEASE HELP !!!!!!!

Mathematics

1 answer:

Vlada [557]3 years ago

7 0

Answer:

23,400

Step-by-step explanation:

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A baker bought 88.9 ounces of coconut. The next day, she used 7.4 ounces of it to make coconut frosting. How much coconut does t

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Answer:

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Step-by-step explanation:

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3 years ago

The volume inside of a sphere is V=4πr33 where r is the radius of the sphere. Your group has been asked to rearrange the formula

Semmy [17]

Answer:

Therefore,

$r=\sqrt[3]{\frac{3V}{4\pi }}$

is the required r

Step-by-step explanation:

Given:

Volume of inside of the sphere is given as

$V=\frac{4}{3} \pi r^{3}$

where r is the radius of the sphere

To Find:

r =?

Solution:

We have

$V=\frac{4}{3} \pi r^{3}$ ......Given

$3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}$

Therefore,

$r=\sqrt[3]{\frac{3V}{4\pi }}$

is the required r

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3 years ago

Find the exact value of sin2 theta given sin theta =5/13, 90°<theta <180°

Zepler [3.9K]

Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}
\\\\\\
therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}
\\\\
-------------------------------\\\\
sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13} \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}$

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