1 Chicken have = 2 legs
1 Cow have = 4 legs
No of cows = x
No of chickens = y
Total no of legs = 4x + 2y = 210.............(1)
Total No of heads = x + y = 84................(2)
x = 84 - y....( from (2) )
Substituting the above equation in (1)
4 ( 84 - y) + 2y = 210
336 - 4y + 2y = 210
336 - 2y = 210
-2y = -126
= y = 63
No of cows = 84-63 = 21
∴ <u><em>Total no of cows = 21</em></u>
<u><em>Total no of chickens = 63</em></u>
Answer:
= x(a+b)(a-b) . x(b+c)(b-c) .x(c+a)(c-a)
m+6n
Step-by-step explanation:
yyou should use a grapher online it does all the work
Work Shown:
|x+6| ≤ 8
-8 ≤ x+6 ≤ 8
-8-6 ≤ x+6-6 ≤ 8-6
-14 ≤ x ≤ 2
