3 years ago

Given f(x)=x+2 and h(x)=1/x-1 evaluate the following function at x=2 [h(x)]^2/f(x)

Mathematics

1 answer:

dlinn [17]3 years ago

7 0

Answer:

$\frac{1}{4}$

Step-by-step explanation:

Substitute x = 2 into both h(x) and f(x)

h(2) = $\frac{1}{2-1}$ = 1 ⇒ (h(2))² = 1

f(2) = 2 + 2 = 4

Hence

$\frac{h(x)^2}{f(x)}$ when x = 2

= $\frac{1}{4}$

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Given f(x)=x+2 and h(x)=1/x-1 evaluate the following function at x=2​ [h(x)]^2/f(x)

Given f(x)=x+2 and h(x)=1/x-1 evaluate the following function at x=2 [h(x)]^2/f(x)