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coldgirl [10]
3 years ago
14

Given f(x)=x+2 and h(x)=1/x-1 evaluate the following function at x=2​ [h(x)]^2/f(x)

Mathematics
1 answer:
dlinn [17]3 years ago
7 0

Answer:

\frac{1}{4}

Step-by-step explanation:

Substitute x = 2 into both h(x) and f(x)

h(2) = \frac{1}{2-1} = 1 ⇒ (h(2))² = 1

f(2) = 2 + 2 = 4

Hence

\frac{h(x)^2}{f(x)} when x = 2

= \frac{1}{4}

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