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goblinko [34]
3 years ago
5

Point x is at 2/3 on a number line point y is the same distance from o as point x has a numerator of 8 what is the demonintor of

the fraction at point y draw a
number line to model the problem
Mathematics
1 answer:
stepladder [879]3 years ago
3 0

people answer please i need this answer

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Consider the following sequence
wlad13 [49]

Answer:

a₇ =  2.375

Step-by-step explanation:

There is a common ratio r between consecutive terms, that is

r = \frac{-76}{152} = \frac{38}{-76} = \frac{-19}{38} = - \frac{1}{2}

This indicates the sequence is geometric with nth term

a_{n} = a₁ (r)^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 152 and r = - \frac{1}{2} , then

a_{n} = 152 (-\frac{1}{2}) ^{n-1} , so

a₇ = 152 (-\frac{1}{2}) ^{6} = 152 × \frac{1}{64} = 2.375

3 0
3 years ago
Read 2 more answers
A baseball team played 154 regular season games. The ratio of the number of games they won to the number of games they lost was
faltersainse [42]

a.

Let

5x = number of games won

2x = number of games lost

The total number of win and lose is 154. So

5x + 2x = 154

Solving for x,

7x = 154

x = 22

Therefore, the number of games won is 5*22=110 and the number of games lost is 2*22 is 44.

b.

Let

6x = first side of the triangle

7x = second side of the triangle

9x = third side of the triangle

The perimeter of a triangle is the total of all sides. So,

6x + 7x + 9x = 88

22x = 88

x = 4

Therefore, the three lengths of the side are 6*4=24, 7*4=28, and 9*4 = 36

Read more on Brainly.com - brainly.com/question/872209#readmore

6 0
4 years ago
Identify the terms of the coefficients of the expression. 8x-20y-10
baherus [9]
The terms of this expression would be 8x,-20y, and -10. The coefficients are the numbers in front of the variable so they would be 8 and 20 because they are accompanied by a variable.
3 0
4 years ago
Need help with these table what do I do?
Greeley [361]

Answer:

just ask it again

Step-by-step explanation:

5 0
3 years ago
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the amount of gasoline used by a car varies jointly as the distance travelled and the square root of the speed.Suppose a car use
klemol [59]

Answer:

200 litres

Step-by-step explanation:

let g be gasoline used, d the distance travelled and s the speed, then the equation relating the quantities is

g = kd\sqrt{s} ← k is the constant of variation

To find k use g = 25, d = 100 and s = 100, then

25 = k × 100 × \sqrt{100} = k × 100 × 10 = 1000k ( divide both sides by 1000 )

0.025 = k

g = 0.025d\sqrt{s} ← equation of variation

When d = 1000 and s = 64, then

g = 0.025 × 1000 × \sqrt{64} = 0.025 × 1000 × 8 = 200

4 0
3 years ago
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