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Answer:
Code is given below along with explanation and output.
Step-by-step explanation:
we can use the method of list comprehension to achieve the given task.
In a list comprehension, we create a sub-list of elements which satisfy specific conditions. the condition i !=x makes sure that x would be excluded in the modified list.
def remove_all(L, x):
return [i for i in L if i != x]
L = [1, 2, 3, 4, 5, 6, 4, 3, 2, 4 ]
print('Before =',L)
L = remove_all(L, 4)
print('After =',L)
Output:
Before = [1, 2, 3, 4, 5, 6, 4, 3, 2, 4]
After = [1, 2, 3, 5, 6, 3, 2]
As you can see we have successfully removed the multiple occurrence of x=4 while preserving the order of the list.
Answer:
Step-by-step explanation:
Given expression is,
f(x) = 8x³ - 6x² - 36x + 27
For zeros of the function,
f(x) = 0
8x³ - 6x² - 36x + 27 = 0
2x²(4x - 3) - 9(4x - 3) = 0
(2x² - 9)(4x - 3) = 0
(2x² - 9) = 0
x² =
x =
x =
Or (4x - 3) = 0
x =
Therefore, all zeros of the given functions are .