Question

Please help! Need soon!

Answer 1

As the equation of this problem would be y=15+3x, there would be 57 seats in the 14th row. 

Answer 2

Answer:

There are 54 seats in 14th row,

In the first 14th row the total seats are 483.

Step-by-step explanation:

Given,

The number of seats in first row = 15,

Also,  3 additional seats in each subsequent row,

⇒ The seats in second row = 15 + 3 = 18,

⇒ The seats in third row = 18 + 3 = 21,

⇒ The seats in fourth row = 21 + 3 = 24,

................................................, so on,........

Thus, the given situation can be written as an AP,

15, 18, 21, 24,...........

Having first term, a = 15,

Common difference, d = 3,

Thus, the number of seats in 14th row,

$a_{14}=a+(14-1)3=15+13(3)=15+39=54$

Also, the total number of seats in total in the first 14th seats,

$S_{14}=\frac{14}{2}[2a+(14-1)d]=7(2\times 15+13(3))=7(30+39)=7(69)=483$