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defon
3 years ago
13

What is 3/4 +3/5 as a mixed number

Mathematics
2 answers:
son4ous [18]3 years ago
8 0

Answer:

<em>1  7/20</em>

Step-by-step explanation: <em> </em><em>3/4+3/5 as a mixed number</em>

<em>Well you start by having 3/4+3/5 and then you multiply 5 times 3 which is 15, then you multiply 3 times 4 is 12. Now you multiply the denomerators which are 5 times 4 is 20 so what I did was I switch the number to on each side so the denomerators are 5 and 4 so I just put the 4 on the left side and then I put the 5 on the other side well you do numerator and the denomerator as the same number so you can multiply the numerator and the denomerator as the same on each side but so like this 5/5 * 3/4+3/5*4/4 now you multiply the numerator adn the denomerator anad you get 15/20+12/20 now you just add so 15+12 is 27 and you just leave the denomerator alone so it is 27/20 so now you have to divide. here is a trick up my sleeve you could do the football long  division so you put it like 27/20. So now you have to figure out what can go into 27 with 20 which is 1 so you put that above the division sign and now you subtract 27 and 20 so that gives you 7 now you take that 7 and bring it above the 20 and not you have 7/20 and now you bring it up over and past the 1 and now you have 1 7/20 or you could say as like this one and seven 20 and can't 20th so I just put 20 so don't mind. I hope this is the answer!!</em>

Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

27 /20 =1 and 7 over 20= 1.35

Step-by-step explanation:

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nadezda [96]

Answer:

Use pythagorean theorem.

Step-by-step explanation:

The length of the shorter sides are 1 & 4

1^2+4^2=c^2

1+16=c^2

17=c^2

So, the length, rounded to the nearest whole inch, would be 4.

To find the perimeter, you need to find the side lengths first.

The short sides are 6 & 7.

6^2+7^2=c^2

36+49=c^2

85=c^2

So the length for that would be 8, in the nearest whole number.

Add all of the side lengths together.

6+7+8= 21

The perimeter is 21.

8 0
3 years ago
Is 0.82 (reapting) rational
Elena-2011 [213]

Answer:

no

Step-by-step explanation:

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3 years ago
Can someone please simplify these using product notation?
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3 years ago
A norman window is constructed by adjoining a semicircle to the top of an ordinary rectangular. Find the dimensions of a norman
Yanka [14]

Answer:

W\approx 8.72 and L\approx 15.57.

Step-by-step explanation:

Please find the attachment.

We have been given that a norman window is constructed by adjoining a semicircle to the top of an ordinary rectangular. The total perimeter is 38 feet.

The perimeter of the window will be equal to three sides of rectangle plus half the perimeter of circle. We can represent our given information in an equation as:

2L+W+\frac{1}{2}(2\pi r)=38

We can see that diameter of semicircle is W. We know that diameter is twice the radius, so we will get:

2L+W+\frac{1}{2}(2r\pi)=38

2L+W+\frac{\pi}{2}W=38

Let us find area of window equation as:

\text{Area}=W\cdot L+\frac{1}{2}(\pi r^2)

\text{Area}=W\cdot L+\frac{1}{2}(\pi (\frac{W}{2})^2)

\text{Area}=W\cdot L+\frac{\pi}{2}(\frac{W}{2})^2)

\text{Area}=W\cdot L+\frac{\pi}{2}(\frac{W^2}{4})

\text{Area}=W\cdot L+\frac{\pi}{8}W^2

Now, we will solve for L is terms W from perimeter equation as:

L=38-(W+\frac{\pi }{2}W)

Substitute this value in area equation:

A=W\cdot (38-W-\frac{\pi }{2}W)+\frac{\pi}{8}W^2

Since we need the area of window to maximize, so we need to optimize area equation.

A=W\cdot (38-W-\frac{\pi }{2}W)+\frac{\pi}{8}W^2  

A=38W-W^2-\frac{\pi }{2}W^2+\frac{\pi}{8}W^2  

Let us find derivative of area equation as:

A'=38-2W-\frac{2\pi }{2}W+\frac{2\pi}{8}W  

A'=38-2W-\pi W+\frac{\pi}{4}W    

A'=38-2W-\frac{4\pi W}{4}+\frac{\pi}{4}W

A'=38-2W-\frac{3\pi W}{4}

To find maxima, we will equate first derivative equal to 0 as:

38-2W-\frac{3\pi W}{4}=0

-2W-\frac{3\pi W}{4}=-38

\frac{-8W-3\pi W}{4}=-38

\frac{-8W-3\pi W}{4}*4=-38*4

-8W-3\pi W=-152

8W+3\pi W=152

W(8+3\pi)=152

W=\frac{152}{8+3\pi}

W=8.723210

W\approx 8.72

Upon substituting W=8.723210 in equation L=38-(W+\frac{\pi }{2}W), we will get:

L=38-(8.723210+\frac{\pi }{2}8.723210)

L=38-(8.723210+\frac{8.723210\pi }{2})

L=38-(8.723210+\frac{27.40477245}{2})

L=38-(8.723210+13.70238622)

L=38-(22.42559622)

L=15.57440378

L\approx 15.57

Therefore, the dimensions of the window that will maximize the area would be W\approx 8.72 and L\approx 15.57.

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3 years ago
Solve equation.<br> 2x-5y=20
Novay_Z [31]
If you solve for x you get:
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</span></span>
If you solve for y you get:
y=(<span><span><span>2/5)</span>x</span>−<span>4</span></span>
5 0
3 years ago
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