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qaws [65]
3 years ago
9

A shop recorded total sales of $2,000 on Monday. On Tuesday, its sales fell by 10%. On Wednesday, sales fell by another 20% comp

ared with Tuesday. From Wednesday to Thursday, sales increased by an amount equal to 25% of Monday’s total sales.
What is the net change, in dollars, in total sales from Monday to Thursday?

The net change, in dollars, in total sales was
Mathematics
2 answers:
IrinaVladis [17]3 years ago
7 0

The net change, in dollars, in total sales was -60

Step-by-step explanation:

A shop recorded total sales of $2,000 on Monday

  • On Tuesday, its sales fell by 10%
  • On Wednesday, sales fell by another 20% compared with Tuesday
  • From Wednesday to Thursday, sales increased by an amount equal to 25% of Monday’s total sales

We need to find the net change in total sales from Monday to Thursday

∵ The total sales in Monday = $2000

∵ The total sales fell by 10% on Tuesday

∵ 2000 × 10% = 2000 × \frac{10}{100} = 200

∴ The total sales fell by $200 on Tuesday

∴ The total sales on Tuesday = 2000 - 200 = 1800

∴ The total sales on Tuesday is $1800

∵ On Wednesday, sales fell by 20% compared with Tuesday

∵ The total sales on Tuesday = $1800

∵ 1800 × 20% = 1800 × \frac{20}{100} = 360

∴ The total sales fell by $360 on Wednesday

∴ The total sales on Wednesday = 1800 - 360 = 1440

∴ The total sales on Wednesday is $1440

∵ The sales increased by an amount equal to 25% of Monday’s

  total sales from Wednesday to Thursday

∵ The total sales on Monday = $2000

∵ 2000 × 25% = 2000 × \frac{25}{100} = 500

∴ The total sales increased by $500 from Wednesday to Thursday

∵ The total sales = $1440 on Wednesday

∴ The total sales from Wednesday to Thursday = 1440 + 500 = 1940

∴ The total sales from Wednesday to Thursday is $1940

∵ The net of change = The total sales on Thursday - the total sales

   on Monday

∵ The total sales on Monday = $2000

∵ The total sales on Thursday = $1940

∴ The net change = 1940 - 2000 = -60

∴ The net change from Monday to Thursday is - $60

The net change, in dollars, in total sales was -60

Learn more:

You can learn more about net change in brainly.com/question/6871421

#LearnwithBrainly

mamaluj [8]3 years ago
3 0

<u>Answer:</u>

The net change in sales is $60

<u>Explanation</u>:

Given the total sales on Monday = $2000

According to question,

Sales on Tuesday will be calculated, 2000 – 10% of 2000 = 2000 – 200 = $1800

Sales on Wednesday will be calculated as,

1800 – 20% of 1800 = 1800 – 360 = $1440

Sales on Thursday = 1430 + 25% of 2000 = 1440 + 500 = $1940

Net change = Sale on Monday – Sales on Thursday

Net change = 2000 – 1940 = $60

Therefore, the net change in sales is $60

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Answer:

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Step-by-step explanation:

Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).

Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),

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at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)

the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)

      Formula : D=\sqrt{(x2-x1)^2+(y2-y1)^2}

⇒                     D = \sqrt{20^2t^2+15(t-1)^2}

Now let           F(t) = D^2(t)

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⇒                     t= 450/1250

⇒                     t= .36 hours

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Answer:

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b) We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

c) No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

Step-by-step explanation:

Part a

Data given and notation  

n=580 represent the random sample taken    

X represent the seafood sold in the country that is mislabeled or misidentified by the people

\hat p=0.25 estimated proportion of seafood sold in the country that is mislabeled or misidentified by the people

\alpha=0.01 represent the significance level (no given, but is assumed)    

p= population proportion of seafood sold in the country that is mislabeled or misidentified by the people

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

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And the 99% confidence interval would be given (0.204;0.296).

Part b

We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

Part c

A government spokesperson claimed that the sample size was too​ small, relative to the billions of pieces of seafood sold each​ year, to generalize. Is this criticism​ valid?

No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

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Step-by-step explanation:

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