Answer:
the gradient is the same= 4
the y intecept is different, one is positive 1 and the other is negative 3
High gloss : total
57 : 57+33
57 : 90
57 ÷ 3 : 90 ÷ 3
19 : 30
Answer: two over three
Step-by-step explanation:

line intercepts y at (0,-2)
Therefore, 
Substitute x = 3 in y =ax-2

To find the x-intercept, y = 0

The slope is 2/3
y-intercept is -2
So two over three
Answer:
slope: 5/7
0.714 mile per hour
Step-by-step explanation:
slope: find the point where the line is right on the line graph, put y/x which is 10/14 make the fraction smaller which is 10/14 = 5/7(I divide the denominator and nominator by 2)
Mile per hour: 5/7 cross multiply with x/1, make into an equation:
7x=5 x 1
7x = 5
x = 0.714
Solution:
Vertical angles are a pair of opposite angles formed by intersecting lines. re vertical angles. Vertical angles are always congruent.
These two angles (140° and 40°) are Supplementary Angles because they add up to 180°:
Notice that together they make a straight angle.
Hence,
From the image
The following pairs form vertical angles

Hence,
One pair of the vertical angles is ∠1 and ∠3
Part B:
Two angles are said to be supplementary when they ad together to give 180°
Hence,
From the image,
The following pairs are supplementary angles

Hence,
One pair of supplementary angles is ∠5 and ∠6