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3 years ago

7

Harley is loading 625 bags of cement in pallets . Each pallet holds 5 bags. How many pallets well she need?

2 answers:

densk [106]3 years ago

6 0

Harley is loading 625 bags of cement in pallets . Each pallet holds 5 bags. How many pallets well she need?

KEYWORD ======> EACH / How Many =======> Divide

Answer ========> 625 / 5 ========> Harley will need 125 Pallets.

Hope that helps!!!!! : )

notka56 [123]3 years ago

4 0

625/5=125
125 is your answer

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Answer:

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$P(X=x)=n_{C_{x}}*p^x*(1-p)^{n-x}$

x is a binomial Random Variable.

Part B:

Value of p=0.8

Value of n=20

Part C:

P(X=15)=0.17456

Part D:

P(X≥15)=0.80417

Part E:

E(x)=16

E(x) tells us that out of 20 tracks the SBIRS will detect from 16 tracks.

Step-by-step explanation:

Part A:

Binomial Distribution is used because the number of tracks and the probability to find the intruding object is constant for all tracks

It means:

$P(X=x)=n_{C_{x}}*p^x*(1-p)^{n-x}$

x is a binomial Random Variable.

Part B:

Value of p=0.8

Value of n=20

Part C:

x=15

$P(X=15)=20_{C_{15}}*0.8^{15}*(1-0.8)^{20-15}\\$

By solving above Expression:

P(X=15)=0.17456

Part D:

P(X≥15)=P(X=15)+P(X=17)+P(X=16)+P(X=18)+P(X=19)+P(X=20)

$P(X=15)=20_{C_{15}}*0.8^{15}*(1-0.8)^{20-15}\\$

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$P(X=17)=20_{C_{17}}*0.8^{17}*(1-0.8)^{20-17}\\P(X=17)=0.20536$

$P(X=18)=20_{C_{18}}*0.8^{18}*(1-0.8)^{20-18}\\P(X=18)=0.13691\\\\P(X=19)=20_{C_{19}}*0.8^{19}*(1-0.8)^{20-19}\\P(X=19)=0.05765\\\\P(X=20)=20_{C_{20}}*0.8^{20}*(1-0.8)^{20-20}\\P(X=20)=0.01153$

Now, Adding Probabilities:

$P(X=15)+P(X=17)+P(X=16)+P(X=18)+P(X=19)+P(X=20)\\=0.17456+0.21819+0.20536+0.13691+0.05765+0.01153\\$

P(X≥15)=0.80417

Part E:

Mean Distribution:

E(x)=n*p

E(x)=20*0.8

E(x)=16

E(x) tells us that out of 20 tracks the SBIRS will detect from 16 tracks.

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