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Lelechka [254]
4 years ago
10

Find the limit of the function algebraically. (2 points) limit as x approaches zero of quantity x squared plus two x divided by

x to the fourth power.

Mathematics
1 answer:
DIA [1.3K]4 years ago
7 0

Answer:

DNE

Step-by-step explanation:

\lim_{x \to \0} \frac{x^{2} +2x}{x^{4} }

As you can see in the picture I attached to this, that as the limit goes to zero from the negative side, it approaches -∞ and from the positive side, it approaches ∞ . hence, the limit doesn't exist.

To show this algebraically, you have to imagine how a number divided by zero looks like, Just know the graph of 1/x and see how the limit to zero doesnot exist. I hope this helps!

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Svetlanka [38]
9898 \frac{1}{2}
7 0
3 years ago
Question 5^ Need help ... ASAP ... your help is really appreciated ...
goblinko [34]

Answer:

See below

Step-by-step explanation:

I think we had a question similar to this before. Again, let's figure out the vertical and horizontal distances figured out. The distance from C at x=8 to D at x=-5 is 13 units while the distance from C at y=-2 to D at y=9 is 11 units. (8+5=13 and 2+9=11, even though some numbers are negative, we're looking at their value in those calculations)

Next, we have to divide each distance by 4 so we can apply it to the ratio. 13/4=\frac{13}{4} and 11/4=\frac{11}{4}. Next, we need to read the question carefully. It's asking us to place the point in the ratio <em>3</em> to <em>1</em> from <em>C</em> to <em>D</em>. The point has to be closer to endpoint D because of this. Let's take each of our fractions, multiply them by 3, then add them towards the direction of endpoint D to get our answer (sorry if that sounds confusing):

\frac{13}{4}*3 = \frac{39}{4}\\ 8-\frac{39}{4} =  \frac{-7}{4}\\\frac{11}{4}*3 = \frac{33}{4}  \\-2+\frac{33}{4} = \frac{25}{4}

Therefore, our point that partitions CD into a 3:1 ratio is (\frac{-7}{4}, \frac{25}{4}).

I'm not sure if there was more to #5 judging by how part B was cut off. From what I can understand of part B, however, I believe that Beatriz started from endpoint D and moved towards C, the wrong direction. She found the coordinates for a 1:3 ratio point.

Also, for #6, since a square is a 2-dimensional object, the answer needs to be written showing that. The answer for #6 is 9 units^2.

7 0
4 years ago
-(m-8) = -8m+29 I dont understand how to do the left side
Temka [501]

-(m-8)= -8m+29

-1(m-8)=-8m+29-------------Note: there is always an invisible 1 in front

-m+8=-8m+29---------------Subtract both sides by -8

-m=-8m+21-------------------Add both sides by +m

0=-7m+21---------------------Add +7m to both sides

7m=21 -------------------------Divide both sides by 7

m=3



6 0
3 years ago
Whoever answers first gets a brainliest . thanks
Svetradugi [14.3K]
To find the number less than x you have to subtract with the larger number .
8.0-2.5 = 5.5
Find the number that greater than x you have to add those to number
8.0+2.5 = 10.5
So
5.5
5 0
4 years ago
Read 2 more answers
Find the value of x for the following angles<br> (6x + 4)degrees and <br> (4x + 6)degrees
MrRissso [65]
(6x + 4) = (4x + 6)
-4                 -4
6x = 4x + 2
-4x     -4x
6x = 2
/6     /6
x = 1/3
4 0
3 years ago
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