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Lelechka [254]
3 years ago
10

Find the limit of the function algebraically. (2 points) limit as x approaches zero of quantity x squared plus two x divided by

x to the fourth power.

Mathematics
1 answer:
DIA [1.3K]3 years ago
7 0

Answer:

DNE

Step-by-step explanation:

\lim_{x \to \0} \frac{x^{2} +2x}{x^{4} }

As you can see in the picture I attached to this, that as the limit goes to zero from the negative side, it approaches -∞ and from the positive side, it approaches ∞ . hence, the limit doesn't exist.

To show this algebraically, you have to imagine how a number divided by zero looks like, Just know the graph of 1/x and see how the limit to zero doesnot exist. I hope this helps!

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P = a + b +c for b what the answer math ​
Elena L [17]

Answer:

p - a - c = b

Step-by-step explanation:

p = a + b + c

subtract a and b from both sides to isolate c

p - a - c = a - a + b

+ c - c

3 0
2 years ago
The following integral requires a preliminary step such as long division or a change of variables before using the method of par
shtirl [24]

Division yields

\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}

Now for partial fractions: you're looking for constants <em>a</em>, <em>b</em>, and <em>c</em> such that

\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}

\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a

which gives <em>a</em> + <em>b</em> = 2, <em>c</em> = 0, and 2<em>a</em> = -7, so that <em>a</em> = -7/2 and <em>b</em> = 11/2. Then

\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}

Now, in the integral we get

\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx

The first two terms are trivial to integrate. For the third, substitute <em>y</em> = <em>x</em> ² + 2 and d<em>y</em> = 2<em>x</em> d<em>x</em> to get

\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}

7 0
2 years ago
21) Martha's aunt bought $26 for 20 plants. Some were
a_sh-v [17]

Answer:

8 carnations and 12 zinnias

Step-by-step explanation:

4 0
2 years ago
Sage and Tom started the month with the same number of talk minutes on their cell phones. Sage talked for 7 minutes with her dad
Paraphin [41]

Answer:

a. Sage and Tom have the same number of talk minutes left on their cell phone plans.

b. y = x - 7

Explanation:

Sage talked for 7 minutes with her dad.

Tom talked for 4 minutes with a friend and 3 more minutes with his mom which means he spoke for :

= 4 + 3

= 7 minutes

They both spoke for 7 minutes and therefore have the same amount of time left.

Algebraic expression:

Assuming the time Tom started with is denoted by x and the time he is left with is denoted by y.

The expression is:

y = x - 7

6 0
2 years ago
What value of n makes the equation true?
otez555 [7]
2/3 n = -12 Write equation

(3/2) 2/3n = -12/1 (3/2) Isolate n

n = -36/2 Simplify

n = -18 Answer




4 0
3 years ago
Read 2 more answers
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