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Vesna [10]
3 years ago
7

Joe spent 15/22 of his pocket money in a story book which costs $75. How many pocket money did he have at first?

Mathematics
2 answers:
fomenos3 years ago
7 0
Well I got $110 75/15=5 then multiply that then 22x5=110
ehidna [41]3 years ago
6 0

Answer:

$51.1

Step-by-step explanation:

If Joe spent 15/22 of his pocket money in a story book which costs $75, he had $51.1 at first.

15/22 of 75 = 51.1363636364 or 51.1

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Technician A says that a cylinder leakage test fills the cylinder with compressed air and the gauge indicates the percentage of
alukav5142 [94]

Answer:

Technician A is correct.

Step-by-step explanation:

Technician A says that a cylinder leakage test fills the cylinder with compressed air, and the gauge indicates the percentage of leakage.

This is correct.

The cylinder leakage test is also called engine leak down test. Here rather than measuring the ability of engine to generate pressure, compressed air is filled in the cylinder via spark plug hole.

8 0
3 years ago
Find the unit price for each size of Jiffy peanut butter and determine which size is the better buy 18 oz. $3.28
Liono4ka [1.6K]
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5 0
3 years ago
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ANTONII [103]
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6 0
3 years ago
To prove :One plus cot square theta into tan theta by sec square theta = cot theta
pickupchik [31]

we are given

\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)

We will simplify left side and make it equal to right side

Left side:

\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)}

we can use trigonometric identity

1+cot^2(\theta)=csc^2(\theta)

we can replace it

\frac{(csc^2(\theta))*tan(\theta)}{sec^2(\theta)}

we know that

csc=1/sin and sec=1/cos

so, we can replace it

and we get

\frac{cos^2(\theta)tan(\theta)}{sin^2(\theta)}

now, we know that

tan =sin/cos

\frac{cos^2(\theta)*sin(\theta)}{sin^2(\theta)*cos(\theta)}

we can simplify it

and we get

\frac{cos(\theta)}{sin(\theta)}

we can also write it as

=cot(\theta)

Right Side:

cot(\theta)

we can see that

left side = right side

so,

\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)......Answer

6 0
3 years ago
Is the following relation a function?
dimulka [17.4K]

Answer:

yes

Step-by-step explanation:

A function is any graph that the x values do not repeat.

You can check this by using this vertical line test

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8 0
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