Okay, let me just make this a little clearer. Hopefully, this is what you meant:
A. y - 8 = -4(x + 4)
B. y - 8 = 4(x + 4)
C. y + 8 = 4(x - 4)
D. y + 8 = -4(x - 4)
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This can also be written as y2 - y1 = m(x2 - x1).
Your M is your slope.
Both A and D have their m as a negative 4. Because you are looking for a positive slope, immediately cancel those answers.
* note that you could have also put them in a more standard form and discovered m which is the x in bx.
Now, you are looking for an equation that contains (4,-8).
Because it is written as y2-y1, your y's are actually points if you were to find another slope or something. This part is a bit hard to explain, but -8 is only found in the y coordinate place in answer B. Your answer would be B. For more explanation on that, there's this great site called coolmath.com and if you search for finding the equation of two points, it explains it much better on there, but I would not want to plagiarize.
The answer is B.
There are many ways to check if the point (1,3) is a solution to the linear equation 
.
Let us check it by expressing y in terms of x.
The given expression is 5x-9y=32. If we add -5x to both sides we will get:
Multiplying both sides by -1 we will get:
In order to isolate y, we will divide both sides by 9 to get:
Now let us plug in the given value of x=1 from the point (1,3). This should give us y=3. Let us see if we get y=3 when we plug x=1 in the above equation.
Thus, we see that when x=1, y=-3 and that 
and hence we conclude that the point (1,3) is not a solution to the original given linear equation 5x-9y=32.
For a better understanding of the explanation given here a graph has been attached. As can be seen from the graph, (1,3) does not lie on the straight line that represents 5x-9y=32, but (1,-3) does lie on it as we had just found out.
Answer:
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Step-by-step explanation:
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Answer:
Congruent segments are simply line segments that are equal in length. Congruent means equal. Congruent line segments are usually indicated by drawing the same amount of little tic lines in the middle of the segments, perpendicular to the segments
Step-by-step explanation:
