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Ostrovityanka [42]
3 years ago
12

If the length of one base of a trapezoid is 5, the length of the other base is 2x + 7, and the length of the midsegment is 6x –

24, what is the value of x? Show equations and all work that leads to your answer.
Mathematics
1 answer:
enyata [817]3 years ago
8 0

Answer:

x = 6

Step-by-step explanation:

The midsegment of a trapezoid is the line parallel to the parallel sides of the trapezoid, which connects the midpoints of the non-parallel sides.

The length of the midsegment of the trapezoid is half the sum of the length of the parallel sides.

i.e,

Length of the midsegment = (1/2) *(Length of base1 + Length of base2)

6x - 24 = (1/2) * (5 + 2x + 7)

12x - 48 = 2x + 12

10x = 60

x=6

∴ x = 6

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For now, we're only going to focus on the very beginning of the problem -- 4c.
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((4*-4)*5)((10(2*2))/(50(5)))+20(-1). You didn't use parentheses to separate the term /50d + 20q, so I'm assuming that the first part of the problem is only divided by just 50d, and not 50d+20q. In the future, be sure to clarify with parentheses. Anyway...
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