Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then
By substitution, we have that
and
.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
In the secant secant theorem,
AP × BP = CP × DP
AP × 6 = 7 × 12
AP = 7 × 2 = 14
Answer: 14
27x^2 - 42x + 12
If x = 2:
27(2)^2 - 42(2) + 12
= 27(4) - 84 + 12
= 108 - 72
= 36
Answer:
I'm sorry i only know (A)
Step-by-step explanation:
Horizontal
Answer:
15% of $67.50 is $10.125 lets round it up to $10.13
Tip: $10.13
Total meal cost: $77.63
Brainly plz :))